Answer:
Explanation:
For lens A
object distance u = - 13.1 cm , focal length f = 6.19 cm
From lens formula
1/v - 1/u = 1/f
1 / v + 1/13.1 = 1/6.19
1/v = 1/6.19 - 1/13.1
= .16155 - .07633
= .08522
v = 11.7 3 cm
For lens B
object distance u = - ( 55.7 - 11.73) = - 43.97 cm , focal length f = 27.9 cm
From lens formula
1/v - 1/u = 1/f
1 / v + 1/43.97 = 1/27.9
1/v = 1/27.9 - 1/43.97
= .03584 - .022742
= .013098
v = 76.35 cm
Image will be formed 76.35 cm behind lens B .
magnification of lens system
= m₁ x m₂ , m₁ is magnification by lens A and m₂ is magnification by lens B
= (11.73 / 13.1) x (76.35 / 43.97)
= .8954 x 1.73
= 1.5547
size of image = total magnification x size of object
= 1.5547 x 6.47
= 10 cm approx. The first image will be real and inverted and second image will be erect with respect to object.
Answer:
-833.3 N/C
Explanation:
Kinetic energy, K, in terms of electric field, E, is given as:
K = qEr
q = charge = e = 1.6 × 10⁻¹⁹C
E = Electric field
r = distance = 0.3m
The electric field can be gotten by making E subject of formula:
E = K/(qr)
The electeic field needed to stop the electrons must be equal in magnitude to the electric field carried by these electrons:
E = (4.0 × 10⁻¹⁷)/(-1.6 × 10⁻¹⁹ * 0.3)
E = -833.3 N/C
This is the electric field needed to stop the electrons.
The negative sign means that the electric field must be in a direction opposite to the motion of the electrons.
0.05*0.2=0.05*0.15+0.015*m2',
m2'=1/6 m/s,
m2'=0.17 m/s
N I C E - D A Y!
Answer:
59.18 kg
Explanation:
use f=ma
f= 580 N
a = 9.8 m/s 2
weigh(m) doesn't change only force(F) changes
