Question

A light-rail commuter train speeds up at a rate of 1.65 m/s 2 and takes 19.0 s to reach its top speed. How far down the tracks does the train go to reach its top speed if starting from rest?

Answer 1

Answer:

297.8 m

Explanation:

We are given that

Acceleration=$a=1.65m/s^2$

Time,t=19 s

We have to find the distance covered by the train when it reach its top speed if starting from rest.

Initial speed=u=0

$s=ut+\frac{1}{2}at^2$

Using the formula

$s=0(19)+\frac{1}{2}\times 1.65(19)^2$

$s=297.8 m$

Hence, the train covered 297.8 m when the train go to reach its top speed if starting from rest.