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Anastaziya [24]
4 years ago
8

A car goes around in a circular curve on a horizontal road at constant speed. what is the direction of the friction force on the

car due to the road?
Physics
1 answer:
velikii [3]4 years ago
3 0
Outside. but I may be wrong
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Which of the following is an SI base unit for measuring length?
irina [24]
Meters it the SI unit for measuring length.
6 0
3 years ago
Read 2 more answers
If a substance has a density of 2.7g/cm3 and a mass of 86.4g, what is its volume?
Gennadij [26K]

Answer:

32cm³

Explanation:

Given parameters:

  Density of substance  = 2.7g/cm³

   Mass of substance  = 86.4g

Unknown:

Volume of substance  = ?

Solution:

Density is the mass per unit volume of a substance.

    Density  = \frac{mass}{volume}

Since the unknown is volume we solve for it;

   mass  = density x volume

   86.4 = 2.7 x volume

    volume  = \frac{86.4}{2.7}   = 32cm³

7 0
3 years ago
Ask Your Teacher The height h in feet reached by a dolphin t seconds after breaking the surface of the water is given by h = −16
kirza4 [7]

Answer:

1 second

Explanation:

h = −16t² + 32t

When, h = 16

16 = −16t² + 32t

Divide each of the numbers by 16

1 = -1t² + 2t

Rearrange the equation

1t²-2t+1 = 0

Solving by the quadratic formula, we get

t=\frac{-(-2)\pm \sqrt{(-2)^2-4\times 1\times 1}}{2\times 1}\\\Rightarrow t=\frac{2\pm 0}{2}\\\Rightarrow t=1\ s

So, time taken by the dolphin to jump out of the water and touch the trainer's hand is 1 second.

3 0
4 years ago
A basketball is tossed upwards with a speed of 5.0\,\dfrac{\text m}{\text s}5.0 s m ​ 5, point, 0, start fraction, start text, m
Hatshy [7]

Answer:

The last one

Explanation:

4 0
3 years ago
A certain alarm clock ticks four times each second, with each tick representing half a period. The balance wheel consists of a t
Semenov [28]

Answer:

a. I=2.77x10^{-8} kg*m^2

b. K=4.37 x10^{-6} N*m

Explanation:

The inertia can be find using

a.

I = m*r^2

m = 0.95 g * \frac{1 kg}{1000g}=9.5x10^{-4} kg

r=0.54 cm * \frac{1m}{100cm} =5.4x10^{-3}m

I = 9.5x10^{-4}kg*(5.4x10^{-3}m)^2

I=2.77x10^{-8} kg*m^2

now to find the torsion constant can use knowing the period of the balance

b.

T=0.5 s

T=2\pi *\sqrt{\frac{I}{K}}

Solve to K'

K = \frac{4\pi^2* I}{T^2}=\frac{4\pi^2*2.7702 kg*m^2}{(0.5s)^2}

K=4.37 x10^{-6} N*m

3 0
3 years ago
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