1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anastaziya [24]
3 years ago
8

A car goes around in a circular curve on a horizontal road at constant speed. what is the direction of the friction force on the

car due to the road?
Physics
1 answer:
velikii [3]3 years ago
3 0
Outside. but I may be wrong
You might be interested in
How much power does it take to lift 30.0 N 10.0 m high in 5.00 s?
Rudik [331]

Power = work/time = (Force times distance)/time

= (30N *10.0m)/5.00s = 300/5 = 60 Watts

7 0
3 years ago
Read 2 more answers
Help me?!?!?!?!?!?!?!?!?!?!?!?!?!
marishachu [46]
The correct field line would be A.
3 0
3 years ago
Read 2 more answers
Uuuuuuuuuuuuuuuuuummmmmmmmmmmmmmmmmmmm help
tatiyna
I think it 32, but i’m not sure
3 0
3 years ago
Read 2 more answers
The magnetic field perpendicular to a single 16.7-cm-diameter circular loop of copper wire decreases uniformly from 0.750 T to z
sammy [17]

Answer:

1.24 C

Explanation:

We know that the magnitude of the induced emf, ε = -ΔΦ/Δt where Φ = magnetic flux and t = time. Now ΔΦ = Δ(AB) = AΔB where A = area of coil and change in magnetic flux = Now ΔB = 0 - 0.750 T = -0.750 T, since the magnetic field changes from 0.750 T to 0 T.

The are , A of the circular loop is πD²/4 where D = diameter of circular loop = 16.7 cm = 16.7 × 10⁻²m

So, ε = -ΔΦ/Δt = -AΔB/Δt= -πD²/4 × -0.750 T/Δt = 0.750πD²/4Δt.

Also, the induced emf ε = iR where i = current in the coil and R = resistance of wire = ρl/A where ρ = resistivity of copper wire =1.68 × 10⁻⁸ Ωm, l = length of wire = πD and A = cross-sectional area of wire = πd²/4 where d = diameter of wire = 2.25 mm = 2.25 × 10⁻³ m.

So, ε = iR = iρl/A = iρπD/πd²/4 = 4iρD/d²

So,  4iρD/d² = 0.750πD²/4Δt.

iΔt = 0.750πD²/4 ÷ 4iρD/d²

iΔt = 0.750πD²d²/16ρ.

So the charge Q = iΔt

= 0.750π(Dd)²/16ρ

= 0.750π(16.7 × 10⁻²m 2.25 × 10⁻³ m)²/16(1.68 × 10⁻⁸ Ωm)

= 123.76 × 10⁻² C

= 1.2376 C

≅ 1.24 C

4 0
3 years ago
Determine the amount of time for polonium-210 to decay to one fourth its original quantity. The half-life of polonium-210 is 138
Tju [1.3M]

Answer:

276 days

Explanation:

1/4 th of the original means <u><em>2 half lives</em></u>

1 half life = 138 days

So,

2 half lives = 276 days

5 0
3 years ago
Other questions:
  • The first mechanized industry was
    8·1 answer
  • A student throws a 130 g snowball at 6.5 m/s at the side of the schoolhouse, where it hits and sticks. What is the magnitude of
    7·1 answer
  • A student pushes a box with a total mass of 50 kg. What is the net force on the box
    11·1 answer
  • A projectile of mass 5 kg is fired with an initial speed of 176 m/s at an angle of 32◦ with the horizontal. At the top of its tr
    5·1 answer
  • Jasmine leaves her house to go for a run. She isn't paying attention to where
    12·1 answer
  • When an earthquake occurs, a huge amount of energy is released.
    9·2 answers
  • Which title goes with this list: Amendments Articles Preamble?
    9·1 answer
  • O que é fisiológicos na areia medica
    6·1 answer
  • 2. Which of the following is not used to calculate kinetic energy?
    11·2 answers
  • A 20 kg cart moving at 4 m/s has how much momentum?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!