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Kaylis [27]
3 years ago
10

Exit ticket

Physics
1 answer:
kirill115 [55]3 years ago
7 0

Why did the narrator use the phrase “fit together like puzzle pieces” to describe how the cells of a developing human embryo form a human face

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Geologists have divided Earth's history into time units, which are regularly based on
Arturiano [62]
They are based on layers of rock the correspond to certain time periods, so my guess would be D.
8 0
3 years ago
The density of a certain type of plastic is 0.75 g/cm3 . If a sheet of this plastic is 10.0 m long, 1.0 m wide, and 1 cm thick,
Oksanka [162]

Answer:

7.5 g

Explanation:

8 0
2 years ago
Issac and Blaise decide to race. They both start at the same position at the same time. Issac runs at 2m/s but decides to take a
FromTheMoon [43]

Let the Blaise runs for time "t" to complete the race

so the total distance he moved is given by

d_1 = 1* t

Now Issac runs for time t = "t - 2*60"

because it took rest for 2 minutes

d_2 = 2*(t - 120)

now it is given that Blaise wins by 10 m distance

d_1 - d_2 = 10

1* t - 2*(t - 120) = 10

t - 2t + 240 = 10

t = 230 s

now the distance moved by Blaise is given by

d_1 = 1*230 = 230 m

6 0
3 years ago
The speed of light is greater in a vacuum than in air or water.<br><br> True or false
Dima020 [189]
True !! Hope I helped you out a bit!
7 0
3 years ago
Read 2 more answers
A 500 kg sack of coal falls vertically onto a 2000 kg railroad flatcar which was initially moving horizontally at 3 m/s. no exte
Zinaida [17]

Since there are no external forces, including friction, act on the flatcar. after the sack rests on the flatcar, we would assume that momentum is conserved. This means that

total momentum of car before collision = total momentum of car after collision.

Recall,

momentum = mass x velocity

From the information given,

mass of car before collision = 2000

velocity of car before collision = 3

Thus,

total momentum of car before collision = 2000 x 3 = 6000

Also,

mass of sack = 500

mass of car and sack after collision = 500 + 2000 = 2500

velocity after collision = v

momentum after collision = 2500 x v = 2500v

Since momentum is conserved, then

6000 = 2500v

v = 6000/2500

v = 2.4

the speed of the flatcar is 2.4 m/s

6 0
1 year ago
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