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tamaranim1 [39]
3 years ago
11

A 535 kg roller coaster car began at rest at the top of a 93.0 m hill. Now it is at the top of the first loop-de-loop. This roll

er coaster’s track is nearly frictionless, so resistance can be ignored. Using g = 9.8 m/s2, what best describes the roller coaster car when it is at the top of the loop-de-loop?
Physics
1 answer:
Nikitich [7]3 years ago
3 0
The correct answer is <span>The car has both potential and kinetic energy, and it is moving at 24.6 m/s.</span>
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If one gram of matter could be completely converted into energy, the yield would be
noname [10]

Answer:

Energy, E=9\times 10^{13}\ J

Explanation:

It is given that,

Mass of matter, m = 1 g = 0.001 Kg

If this matter is completely converted into energy, we need to find the yield. The mass of an object can be converted to energy as :

E=mc^2

c = speed of light

E=0.001\ kg\times (3\times 10^8\ m/s)^2

E=9\times 10^{13}\ J

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5 0
3 years ago
Josh rolled a bowling ball down a lane in 2.5 seconds. The ball travelled at a constant acceleration of 1.8 m/s/s down the lane
IRISSAK [1]
<span> Ok, so slope of the lane gives the ball a constant acceleration of 1.8 m/s for 2.5 s
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6 0
3 years ago
An object in circular motion has velocity that is constantly changing. The direction of the acceleration is
sertanlavr [38]

An object in circular motion has velocity that is constantly changing.

The direction of the acceleration is from the object toward the center of the  circular path the object is following.

8 0
3 years ago
I don't get the flat line on a graph. on a distance/speed or motion graph, they say it is not moving. that is what I don't get i
timofeeve [1]
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4 0
4 years ago
A freight train rolls along a track with considerable momentum. If it were to roll at the same speed but had twice as much mass,
fomenos

Answer:

The momentum would be doubled

Explanation:

The magnitude of the momentum of the freight train is given by:

p=mv

where

m is the mass of the train

v is its speed

In this problem, we have that the speed of the train is unchanged, while the mass of the train is doubled:

m'=2m

therefore, the new momentum is

p'=m'v=(2m)v=2(mv)=2p

so, the momentum has also doubled.

7 0
3 years ago
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