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tamaranim1 [39]
2 years ago
11

A 535 kg roller coaster car began at rest at the top of a 93.0 m hill. Now it is at the top of the first loop-de-loop. This roll

er coaster’s track is nearly frictionless, so resistance can be ignored. Using g = 9.8 m/s2, what best describes the roller coaster car when it is at the top of the loop-de-loop?
Physics
1 answer:
Nikitich [7]2 years ago
3 0
The correct answer is <span>The car has both potential and kinetic energy, and it is moving at 24.6 m/s.</span>
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svetlana [45]
The actual answer is 7/100
4 0
3 years ago
5. To increase this characteristic of contentment in my life, I need to...
Anon25 [30]

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4 0
2 years ago
A firework is launched with a force of 700 N and a momentum of 200 kg-m/s. How much time before is explodes?
8_murik_8 [283]

Answer:

t = 0.28 seconds

Explanation:

Given that,

Force acting on a firework, F = 700 N

The momentum of the firework, p =200 kg-m/s

We need to find the time before it explodes. Ket the time be t. We know that, the rate of change of momentum is equal to external frce. So,

F=\dfrac{P}{t}\\\\t=\dfrac{P}{F}\\\\t=\dfrac{200}{700}\\t=0.28\ s

So, the required time is equal to 0.28 seconds.

7 0
2 years ago
All of the following are factors affecting flow rate except what?
faust18 [17]

Answer:

c. Vessel side holes

Explanation:

  • The "Poiseuille formula" which is given by \\\begin{aligned} \small Q& =  \small \frac{\pi r^4}{8 \eta}.\frac{\Delta P}{\Delta L}\\\end{aligned} describes the volumetric flow rate (\small Q) through tubular sections.
  • Here, \Delta P,\,\, \Delta L,\,\, r,\,\, \eta represent the injection pressure difference, the length of the section, the radius of the section and the viscosity index of the fluid that flows through the section respectively.
  • With this, one can confirm that all the factors except the vessel side holes affect the flow rate.
  • Side holes, however, are a factor that could give a measure of how much volume would flow to a particular location. In such a situation the flow rate remains unchanged and one location would receive a lower volume (not the whole) as some volume would spill out at the side holes.

#SPJ4

5 0
1 year ago
PLS HELP. A flatbed car of a train moves 8 m/s to the east. A jogger runs along to top the flatbed car (which is not very safe)
jonny [76]

Answer:

2 m/s

Explanation: Given that a flatbed car of a train moves 8 m/s to the east. A jogger runs along to top the flatbed car (which is not very safe) with a velocity of 6 m/s to the west.

Since the jogger is moving in an opposite direction to the direction of the train, and velocity is the distance covered in a specific direction, the jogger will be moving at a velocity relative to the velocity of the train.

Velocity = (8 - 6) m/s

Velocity = 2 m/s

Therefore, the jogger will be moving at the speed of 2 m/s

5 0
2 years ago
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