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gregori [183]
3 years ago
9

Does beryllium (Be) or Sodium (Na) have the same electron arrangement as Magnesium (Mg)? Why?

Chemistry
1 answer:
Finger [1]3 years ago
3 0

Answer:

Na has the most similar configuration.

Explanation:

Na electron configuration: 1s²2s²2p⁶3s¹ or [Ne] 3s₁

Mg electron configuration: 1s²2s²2p⁶3s² or [Ne] 3s²

Be electron configuration: 1s²2s² or [He] 2s²

This is because Na and Mg are right next to each other in the same period (horizontal).

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How many moles are there in 13g of KMnO4?
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0.08 moles

Explanation:

Relative atomic mass of KMnO4 = K + Mn + O4 = 39 + 55 + 16 x 4 = 158

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3 years ago
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Identify the correct coefificients to balance it<br> -C3H8+O2 to -CO2 +-H2O
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Answer:

{\rm 1\; C_3H_8} + {\rm 5\; O_2} \to {3\; \rm CO_2} + {4\; \rm H_2O}.

Explanation:

{\rm ?\; C_3H_8} + {\rm ?\; O_2} \to {?\; \rm CO_2} + {?\; \rm H_2O}.

Among the four species in this reaction, \rm C_3H_8 is species with the largest number of atoms per molecule. Assume that the coefficient of this compound is 1.

{\rm 1\; C_3H_8} + {\rm ?\; O_2} \to {?\; \rm CO_2} + {?\; \rm H_2O}.

Number of atoms on the left-hand side of the reaction:

  • \rm C: 1 \times 3 = 3.
  • \rm H: 1 \times 8 = 8.
  • \rm O: not found yet.

By the conservation of atoms, the number of atoms on the right-hand side of the reaction should match those on the left-hand side. In this reaction, \rm CO_2 is the only product with carbon atoms, whereas \rm H_2O is the only product with hydrogen atoms. These 3 carbon atoms and 8 hydrogen atoms would correspond to:

  • 3 / 1 = 3 \rm CO_2 molecules, and
  • 8 / 2 = 4 \rm H_2O molecules.

{\rm 1\; C_3H_8} + {\rm ?\; O_2} \to {3\; \rm CO_2} + {4\; \rm H_2O}.

Number of atoms on the right-hand side of the reaction:

  • \rm C: 3 \times 1 = 3.
  • \rm H: 4 \times 2 = 8.
  • \rm O: 3 \times 2 + 4 \times 1 = 10.

The number of \rm O atoms on the left-hand side should match those on the right-hand side. In this reaction, \rm O_2 is the only reactant with \rm O\! atoms. These 10 \rm \! O atoms would correspond to:

  • 5 \rm O_2 molecules.

{\rm 1\; C_3H_8} + {\rm 5\; O_2} \to {3\; \rm CO_2} + {4\; \rm H_2O}.

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