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algol13
3 years ago
6

Given the reaction: HNO2 (aq) <-> H+ (aq) + NO2- (aq); write the ionization constant for the reaction.

Chemistry
1 answer:
Nuetrik [128]3 years ago
4 0

Answer:

see explanation

Explanation:

HNO₂ ⇄ H⁺ + NO₂⁻

Ka = [H⁺][NO₂⁻]/[HNO₂]

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3 0
3 years ago
If you mix a 25.0mL sample of a 1.20m potassium sulfide solution with 15.0 mL of a 0.900m basium nitrate solution and the reacti
ddd [48]

Answer:

Limiting reagent: barium nitrate

Theoretical yield: 2.29 g BaS

Percent yield: 87%

Explanation:

The corrected balanced reaction equation is:

K₂S + Ba(NO₃)₂ ⇒ 2KNO₃ + BaS

The amount of potassium sulfide added is:

(25.0 mL)(1.20mol/L) = 30 mmol

The amount of barium nitrate added is:

(15.0mL)(0.900mol/L = 13.5 mmol

Since the reactant react in a 1:1 molar ratio, barium nitrate is the limiting reagent. If all of the limiting reagent reacts, the amount of barium sulfide produced is:

(13.5 mmol Ba(NO₃)₂)(BaS/Ba(NO₃)₂ ) = 13.5 mmol BaS

Converting this amount to grams gives the theoretical yield of BaS (molar mass 169.39 g/mol).

(13.5 mmol)(169.39 g/mol)(1g/1000mg) = 2.29 g BaS

The percent yield is calculated as follows:

(actual yield) / (theoretical yield) x 100%

(2.0 g) / (2.29 g) x 100% = 87%

6 0
3 years ago
A sample of 35.1 g of methane gas has a volume of 5.20 l at a pressure of 2.70 atm. calculate the temperature of the gas.
melisa1 [442]
We can use the ideal gas equation to determine the temperature with the given conditions of mass of the gas, volume, and pressure. The equation is expressed
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6 0
3 years ago
What atoms in water are attracted to Chlorine?
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Answer: hydrogen and oxygen

Explanation:

3 0
3 years ago
A weather balloon was initially at a pressure of 0.950 atm, and its volume was 35.0 L. The pressure decreased to 0.750 atm, with
puteri [66]

Answer: The change in volume will be 9.30 L

Explanation:

To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

P_1V_1=P_2V_2

where,

P_1\text{ and }V_1 are initial pressure and volume.

P_2\text{ and }V_2 are final pressure and volume.

We are given:

P_1=0.950atm\\V_1=35.0L\\P_2=0.750atm\\V_2=?L

Putting values in above equation, we get:

0.950\times 35.0L=0.750\times V_2\\\\V_2=44.3L

The change in volume will be (44.3-35.0)L = 9.30 L

7 0
3 years ago
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