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GuDViN [60]
2 years ago
8

When a candle burns what changes are observed?

Chemistry
1 answer:
dexar [7]2 years ago
3 0

Answer:

it's state changes from solid to liquid

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E the table below for the next three questions.
Sliva [168]

Answer:

Explanation:i would go wit d

6 0
3 years ago
1) Ions are formed between positive or negative charge.
RSB [31]

Answer:

1. No 1 looks like a statement and not a question.

2.Ionic compounds are usually formed from the transfer of electrons from metals to Non metals. All others are Ionic compounds except HCl(Its a covalent compound).

3. The Formula would be K2S. Exchange of Radicals takes place. Sulphur has a -2 charge and potassium has a +1 charge. when they both exchange radicals... The compound is K2S.

4.Group 1 elements have only 1 electron in their outermost shell.

5. its charge will be +1 because it loses the 1 electron in its outermost shell.

6.Group 2 elements have 2electrons in their Valence shell.

7.Already answered. same as No 5.

8. Group 16;Also known as group 6. They have only 6 electrons in their outermost shell.

9.When they want to become stable... they acquire 2electrons to complete their octet... so they possess a -2 charge by forming an ion.

10. i)They form ions when Dissolve in solutions

ii) They are hard and brittle

iii) They have high boiling points

3 0
3 years ago
90 grams of NaNO3 were added to solution at 10 degrees Celsius. What type of solution was formed?
vichka [17]

Answer:

friend me on here and imma send you the link Explanation:

4 0
3 years ago
What would be the volume of 0.500 mole of an ideal gas at a temperature of 273.15 Kelvins and 1 atm?
uysha [10]

Answer:

V = 11.21 L

Explanation:

Given data:

Volume of helium = ?

Number of moles = 0.500 mol

Temperature = 273.15 K

Pressure of gas = 1 atm

Solution:

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L/ mol.K

V = nRT/P

V = 0.500 mol ×  0.0821 atm.L/ mol.K  × 273.15 K / 1 atm

V = 11.21 L / 1

V = 11.21 L

8 0
3 years ago
The exhaust gas from an automobile contains 3% by volume of carbon monoxide (CO). Express this concentration in mg/m3 at 25oC an
ser-zykov [4K]

Answer:

24540\frac{mg}{m^3}

Explanation:

Hello,

In this case, since the 3% by volume is represented as:

\frac{3L\ CO}{L\ gas}

By using the ideal gas equation we compute the density of CO:

\rho =\frac{MP}{RT} =\frac{28g/mol*1atm}{0.082\frac{atm*L}{mol*K}*298K}= 0.818g/L

Then we apply the conversion factors as follows:

=\frac{3L\ CO}{100L\ gas}*\frac{0.818g\ CO}{1L\ CO} *\frac{1000mg\ CO}{1g\ CO} *\frac{1000L\ gas}{1m^3\ gas} \\\\=24540\frac{mg}{m^3}

Regards.

4 0
3 years ago
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