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GuDViN [60]
2 years ago
8

When a candle burns what changes are observed?

Chemistry
1 answer:
dexar [7]2 years ago
3 0

Answer:

it's state changes from solid to liquid

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2. (1 point) How many electrons available for bonding does Helium (He) have?
Romashka-Z-Leto [24]

Answer:

Helium has 2 electrons

Explanation:

If this is correct or helpful pls consider brainliest!

3 0
3 years ago
If hershey and chase had used radioactive oxygen in their experiments instead of phosphorus and sulfur, what results would they
Ugo [173]
The real situation with this is that if since both proteins and DNA contain carbon and oxygen, both molecules in the phage progeny would have received the radioactive isotopes. Hershey and Chase would have been unable to isolate only DNA molecules or proteins that contain the radioactive isotopes of these elements. 
5 0
3 years ago
An electrochemical cell is constructed such that on one side a pure lead electrode is in contact with a solution containing Pb2+
Ugo [173]

Answer:

-490.7 K

Explanation:

Given:

[Ni^2+]= 0.4 M

[Pb^2+]=0.002 M

∆V= -0.012 V

VNi= -0.250V

VPb= -0.126V

F= 96500 C

R= 8.314 JK-1 mol-1

n= 2

From

T= -nF/R [∆V-(VNi-VPb)/ln [Pb2+]/[Ni2+]]

T= 2(96500)/8.314[ (-0.012) -(-0.250) - (-0.126))/ln[0.002]/[0.4]

T= 23213.856(0.112/(-5.298))

T= -490.7 K

4 0
3 years ago
How many moles of lithium are present in a sample that contains 2.45x10^87 formula units of Li2SO4?​
ddd [48]

The answer is: 8.14·10⁶³ moles of lithium are present.

N(Li₂SO₄) = 2.45·10⁸⁷; number of formula units of lithium sulfate.

n(Li₂SO₄) = N(Li₂SO₄) ÷ Na.

n(Li₂SO₄) = 2.45·10⁸⁷ ÷ 6.022·10²³ 1/mol.

n(Li₂SO₄) = 4.07·10⁶³ mol; amount of lithium sulfate

In one molecule of lithium sulfate, there are two atoms of lithium.

n(Li₂SO₄) : n(Li) = 1 : 2.

n(Li) = 2 · 4.07·10⁶³ mol.

n(Li) = 8.14·10⁶³ mol; amount of lithium atoms.

3 0
3 years ago
Write a word equation for this reaction S + 02 → SO2<br>Whoever Answer right will get brainliest ​
storchak [24]

\huge \mathcal{Answer࿐ }

The word equation for above chemical equation is :

Sulphur + Oxygen \rightarrow Sulphur dioxide

_____________________________

\mathrm{ \#TeeNForeveR}

6 0
3 years ago
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