The duration (i.e time) of the impact, given that the head impact was 1770 N is 0.005 s
<h3>How do I determine the duration (i.e time)?</h3>
Impulse is defined as the change in momentum of an object. It is expressed as:
Impulse = change in momentum
Impulse = final momentum – Initial momentum
Impule = m(v - u)
Impulse = force × time
Impulse = Ft
Thus,
Ft = m(v - u)
Where
- F is the force
- t is the time
- m is the mass
- u is the initial velocity
- v is the final velocity
Now, we can obtain the duration (i.e time) of the impact. Details below:
- Force (F) = 1770 N
- Initial velocity = 2.09 m/s
- Mass (m) = 4.12 Kg
- Final velocity = 0 m/s
- Duration (t) =?
Ft = m(v + u) since the collision came to a stop
1770 × t = 4.12 × (0 + 2.09)
1770 × t = 4.12 × 2.09
Divide both sides by 1770
t = (4.12 × 2.09) / 1770
t = 0.005 s
Thus, the duration is 0.005 s
Learn more about time:
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Solution
x(t) = 8 cos t, x(5π/6)= 8 cos(<span>5π/6)
</span>cos(5π/6)=cos(3π/6 + 2π/6 )=cos(π/3 +π/2)= - sin π/3 (cos (x+<span>π/2)= -sinx)
</span>x(t) = -8sin <span>π/3 = - 4 .sqrt3
</span>v(t) = -8sint = -8sin (π/3 +<span>π/2)= -8 cosπ/3 </span>(sin (x+π/2)= cosx)
v(t) =<span> -8 cosπ/3 = -8/2= - 4
</span>a(5π/6) = - 8cost = -(- sin π/3)= 4 .<span>sqrt3
</span>a(5π/6) = 4 .<span>sqrt3</span>
Answer:
area is 2d volume is 3d
Explanation:
Area refers to the size of two-dimensional surface. Volume refers to the size of a three-dimensional space.
The beginning development of a
star is marked by a supernova explosion, with the gases present in the nebula
being forced to scatter. As the star shrinks, radiation of the surface increases
and create pressure on the outside shell to push it away and forming a
planetary nebula or white dwarf.
