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2 years ago

When 1.5 kg of mass turns into energy, how much energy is released? Find the equation, substitution, and number with units.

Physics

1 answer:

a_sh-v [17]2 years ago

8 0

Explanation:

$from \: einstein \: equation : \\ E = m {c}^{2} \\ E = 1.5 \times {(3 \times {10}^{8} )}^{2} \\ E = 1.35 \times {10}^{17} \: joules$

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3 years ago

When we apply the energy conversation principle to a cylinder rolling down an incline without sliding, we exclude the work done

NikAS [45]

Answer:

D. the linear velocity of the point of contact (relative to the inclined surface) is zero

Explanation:

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3 years ago

Explain why a Merry-Go-Round and a Ferris Wheel have a constant acceleration when they are moving.

luda_lava [24]

Explanation:What is centripetal acceleration?

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Acceleration is a change in velocity, either in its magnitude—i.e., speed—or in its direction, or both. In uniform circular motion, the direction of the velocity changes constantly, so there is always an associated acceleration, even though the speed might be constant. You experience this acceleration yourself when you turn a corner in your car—if you hold the wheel steady during a turn and move at constant speed, you are in uniform circular motion. What you notice is a sideways acceleration because you and the car are changing direction. The sharper the curve and the greater your speed, the more noticeable this acceleration will become. In this section we'll examine the direction and magnitude of that acceleration.

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3 years ago

Which statements about Earth’s core help explain Earth’s magnetic field? Select three options.

Evgen [1.6K]

Answer: B,E,F

Explanation:

(B) the inner core is solid. (E) the outer core is liquid and moving. (F) Earth's core is composed of iron and nickel

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3 years ago

Read 2 more answers

At the instant the traffic light turns green, an automobile that has been waiting at an intersection starts ahead with a constan

oksian1 [2.3K]

Answer:

(A) Distance taken by automobile to overtake truck is 175.23 m

(B) Final speed of the automobile is 29.6 m/s.

Explanation:

According to the problem, the automobile is at rest, so its initial speed is zero and the automobile is moving with constant acceleration.

The general equation of motion is:

d = ut + 0.5at² .....(1)

Here d is distance, a is acceleration, t is time and u is initial speed.

The distance (d₁) travel by the automobile after green light in time t is given by the relation :

d₁ = u₁t + 0.5at²

We know that its initial velocity is zero i.e. u = 0 m/s.

d₁ = 0.5at² ......(2)

The truck is moving with constant speed, so its acceleration is zero. Therefore, the distance covered by the truck using equation (1) is;

d₂ = u₂t .......(3)

Since, the distance travelled by automobile and truck are same. Hence,

d₁ = d₂

0.5at² = u₂t

t = 2u₂/a

Substitute 14.8 m/s for u₂ and 2.50 m/s² for a in the above equation.

t = $\frac{2\times14.8}{2.50}$

t = 11.84 s

(A) Distance travelled by automobile, d = u₂t =14.8 x 11.84 = 175.23 m

(B) Final speed of the automobile is given by the relation:

v = u + at

v = 0 + 2.50 x 11.84

v = 29.6 m/s

4 0

3 years ago