Rutherford bohr pretty sure
<span>-5230 J
Given the above data, the piece of metal raised the temperature of 250.0 grams of water from 20.0°C to 25.0°C. So there was a change of 5.0°C
The specific heat of water is 4.184 joules per gram which is the amount of energy needed to rais</span>
Answer:
0.6 Ω
Explanation:
From the question given above, the following data were obtained:
Voltage (V) = 12 V
Current (I) = 20 A
Resistance (R) =?
From Ohm's law,
V = IR
Where:
V => is the voltage
I => is the current
R => R is the resistance
With the above formula, we can obtain the resistance as follow:
Voltage (V) = 12 V
Current (I) = 20 A
Resistance (R) =?
V = IR
12 = 20 × R
Divide both side by 20
R = 12 / 20
R = 0.6 Ω
Thus the resistance is 0.6 Ω
The answer you are looking for is true
Answer:
Explanation:
Relation of with is given by the formula:
where,
= equilibrium constant in terms of partial pressure
= equilibrium constant in terms of concentration
R = Gas constant
T = temperature
= change in number of moles of gas particles =
when = 0
a)
= change in number of moles of gas particles =
b)
= change in number of moles of gas particles =
c)
= change in number of moles of gas particles =
d)
= change in number of moles of gas particles =
Thus for reaction , , as = 0