Matthew was working with different concentrations of hydrochloric acid in the lab. Which of these would BEST describe the result
2 answers:
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According to the information in the graph, it can be inferred that the amount of solute that will precipitate out of solution at 20°C is 130 grams.
<h3>How to calculate the amount of solute that precipitates out of solution?</h3>To calculate the amount of solute that precipitates out of solution we must identify the solute data at 80°C and 20°C and identify the difference as shown below:
- Quantity of solute at 80°C: 170 grams.
- Quantity of solute at 20°C: 40 grams.
- 170 grams - 40 grams = 130 grams
According to the above, the amount of solute that will precipitate out of solution due to the change in temperature is 130 grams of KNO3.
Note: This question is incomplete because the graph is missing. Here is the graph
Learn more about solute in: brainly.com/question/7932885
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Answer:
0.22M
Explanation:
We will be using the law of dilutions. We are simply increasing the amount of solvent to create a larger volume of solution.
So: moles before dilution = moles after dilution & . And M = moles/liter of solution, so if we express this as moles = M x
.
That is how we derive the formula we will be using:
or
Applying this formula to our problem, we can substitute the variables with the given values to find the molarity of the dilute solution.
M1 = 3.5M
V1 = 18.8mL
M2 = ?
V2 = 296.6mL
Equation: (3.5M)(18.8mL) = (296.6mL)(M2)
==> 65.8M*mL = 296.6mL * M2
==> M2 = (65.8 M*mL)/296.6mL
==> M2 = 0.22M