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Lena [83]
3 years ago
12

Which has the largest atomic radius calcium bromide barium and astatine

Chemistry
2 answers:
Fantom [35]3 years ago
7 0
The one with the largest atomic radius is barium 

Hoped this helped:)
gavmur [86]3 years ago
6 0

Answer : Barium has the largest atomic radius.

Explanation :

The periodic trend observed with respect to atomic radius is explained below.

Across a period : As we move from left towards right across a period, atomic radius decreases.

This happens because as we move towards right, an extra electron gets added to the same shell. But as we move towards right, the effective nuclear increases. As a result nucleus pulls the outer electrons more strongly which results in shrinking of the atom.

Down the group : As we move down the group, the atomic radius increases.

Because as we move down, an extra shell gets added to the atom. Due to this size of the atom increases.

If we look at the positions of the given elements , we see that Calcium and Bromine are present in fourth period whereas Barium and Astatine are present in sixth period.

According to periodic trend observed for group, Barium and Astatine would have larger atomic radii than Calcium and Bromine.

If we apply periodic trend observed across a period, we can say that Barium is larger than Astatine because it is more towards left .

Therefore the atom with largest radius is Barium.

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Zigmanuir [339]

<u>Answer:</u> The concentration of original sulfuric acid solution is 1.62 M

<u>Explanation:</u>

Let the original concentration of sulfuric acid be 'x' M

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated sulfuric acid solution

M_2\text{ and }V_2 are the molarity and volume of diluted sulfuric acid solution

We are given:

M_1=xM\\V_1=25.00mL\\M_2=?M\\V_2=250.0mL

Putting values in above equation, we get:

x\times 25.00=M_2\times 250.0\\\\M_2=\frac{x\times 25.0}{250}=\frac{x}{10}

Now, to calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=\frac{x}{10}M\\V_1=10.00mL\\n_2=1\\M_2=0.1790M\\V_2=18.07mL

Putting values in above equation, we get:

2\times \frac{x}{10}\times 10.00=1\times 0.1790\times 18.07\\\\x=\frac{1\times 0.1790\times 18.07\times 10}{2\times 10.00}=1.62M

Hence, the concentration of original sulfuric acid solution is 1.62 M

5 0
4 years ago
The empirical formula of a gaseous fluorocarbon is CF2. At a certain temperature and pressure, a 1-L volume holds 8.93 g of this
dimaraw [331]

Answer:

C₄F₈

Explanation:

Using their mole ratio to compute their mass

molar mass of carbon = 12.0107 g/mol

molar mass of fluorine gas = 37.99681

let x = mass of carbon

given mass of fluorine = 1.70 g

x / 12.01067 = 1.70 / 37.99687

cross multiply

x = ( 1.70 × 12) / 37.99687 = 20.4 / 37.99687 = 0.53688 g

mass of one mole of CF₂ = 0.53688 + 1.70 = 2.23688 g

number of mole of CF₂ = 8.93 g / 2.23688 = 3.992 approx 4

molecular formula of CF₂ = 4 (CF₂) = C₄F₈

3 0
3 years ago
How many particles are in 12.47 grams of NaCl?
jeka94
If we are talking about moles then the answer to that is 0.22
5 0
3 years ago
What is the total number of valence electrons in the lewis structure of sebr2o?
zloy xaker [14]

Answer:

15.4: Lewis Structures: Counting Valence Electrons

Explanation:

3 0
2 years ago
Mass is measured using _____.
oee [108]
Kilograms? im assuming. bcz weight is like newtons or sum shii..
4 0
3 years ago
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