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3 years ago

Which has the largest atomic radius calcium bromide barium and astatine

Chemistry

2 answers:

Fantom [35]3 years ago

7 0

The one with the largest atomic radius is barium

Hoped this helped:)

gavmur [86]3 years ago

6 0

Answer : Barium has the largest atomic radius.

Explanation :

The periodic trend observed with respect to atomic radius is explained below.

Across a period : As we move from left towards right across a period, atomic radius decreases.

This happens because as we move towards right, an extra electron gets added to the same shell. But as we move towards right, the effective nuclear increases. As a result nucleus pulls the outer electrons more strongly which results in shrinking of the atom.

Down the group : As we move down the group, the atomic radius increases.

Because as we move down, an extra shell gets added to the atom. Due to this size of the atom increases.

If we look at the positions of the given elements , we see that Calcium and Bromine are present in fourth period whereas Barium and Astatine are present in sixth period.

According to periodic trend observed for group, Barium and Astatine would have larger atomic radii than Calcium and Bromine.

If we apply periodic trend observed across a period, we can say that Barium is larger than Astatine because it is more towards left .

Therefore the atom with largest radius is Barium.

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3 years ago

1.674×10-4 mol of an unidentified gaseous substance effuses through a tiny hole in 86.6 s. Under identical conditions, 1.715×10-

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<h2>Answer:</h2>

44.06 g/mol

<h3>Explanation:</h3>

We are given;

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Number of moles of Argon gas as 1.715×10^-4 mol
Time of effusion of Argon gas is 84.5 s

We are supposed to calculate the molar mass of unidentified gas

<h3>Step 1: Calculate the effusion rates of each gas</h3>

Effusion rate = Number of moles/time

Effusion rate of unidentified gas (R₁)

= 1.674×10^-4 mol ÷ 86.6 s

= 1.933 × 10^-6 mol/s

Effusion rate of Argon gas (R₂)

= 1.715×10^-4 mol ÷ 84.5 sec

= 2.030 × 10^-6 mol/s

<h3>Step 2: Calculate the molar mass of unidentified gas</h3>

Assuming the molar mass of unidentified gas is x;
We can use the Graham's law of effusion to find x;
According to Graham's law of diffusion;

$\frac{R_{1}}{R_{2}}}=\frac{\sqrt{MM_{Ar}}}{\sqrt{X}}$

But, Molar mass of Argon is 39.948 g/mol

Therefore;

$\frac{1.933*10^-6mol/s}{2.030*10^-6mol/s}}=\frac{\sqrt{39.948}}{\sqrt{X}}$

$0.9522=\frac{\sqrt{39.948}}{\sqrt{X}}$

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x = 44.06 g/mol

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4 years ago

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3 years ago

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maksim [4K]

The question is incomplete, here is the complete question:

Calculate the volume in liters of a 0.13 M potassium dichromate solution that contains 200. g of potassium dichromate . Round your answer to 2 significant digits.

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<u>Explanation:</u>

To calculate the volume of solution, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

We are given:

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3 years ago