We use the given masses of the reactants to calculate the moles of Mn and Cl. Empirical formula represents the simplest mole ratio of atoms present in a compound.
Moles of Mn =
Moles of Cl = = 0.710 mol Cl
Simplest mole ratio:
So the empirical formula is
Bromine has 45 of neutrons
The % error in the student’s data is
Correct score - run score/ correct score * 100
In run 1 we have
0.2542 - 0.2541/0.2542 * 100 = 0.000393391031 = 0.03933%
In run 2 we have
0.2542 - 0.2668/0.2542 * 100 = -0.00495672699 = -0.495%
In run 3 we have
0.2542 - 0.2549/0.2542 * 100 = -0.00275373721 = -0.275%
And run 4 we have
0.2542 - 0.2554/0.2542 * 100 = 0.00495672699 = 0.495
The spread are 0.2542 - 0.2541 = 0.0001 and 0.2542 - 0.2668 = -0.0126
Also 0.2542 - 0.2549 = -0.0007 and 0.2542 - 0.2554 = -0.0012
Divide the KCO3 molar mass (138.205g) by 85.62g. You will get 1.614 mol. It is 1.614 because 85.62 has 4 sig figs. Your answer must contain 4.
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I looked this up but hope it helps!