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Masteriza [31]
2 years ago
6

Animals inherit traits from their parents. They pass some of these same traits on to their children. Suppose a pair of animals h

as a trait that helps them survive in their environment. They pass this trait on to their children. What effect will that probably have on the children? A. The children will be more likely to survive than if they did not have the trait. B. It will not affect the children. C. The children will be more likely to survive than their parents were. D. The children will be able to adapt if the environment changes.
Chemistry
1 answer:
Fantom [35]2 years ago
8 0

Answer:

A. The children will be more likely to survive than if they did not have the trait.

Explanation:

Process of elimination

B. It will not affect the children.

Cannot be true, if it didn't impact the children then how would survival of the fittest work?

D. The children will be able to adapt if the environment changes.

That just... not how adapting works when it comes to evolution.

C. The children will be more likely to survive than their parents were

Everyone has the same trait, everyone is equal in that regard.

A. The children will be more likely to survive than if they did not have the trait.

"Suppose a pair of animals has a trait that helps them survive in their environment." The trait helps them survive. Not having the trait makes them less likely to survive. A is correct

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Answer:

6.50 g of Hydrogen

Explanation:

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5 0
1 year ago
A student dissolves 3.9g of aniline (C6H5NH2) in 200.mL of a solvent with a density of 1.05 g/mL . The student notices that the
Tresset [83]

Answer:

a. Molarity= M =2.1x10^{-1}M

b. Molality= m=2.0x10^{-1}m

Explanation:

Hello,

In this case, given the information about the aniline, whose molar mass is 93g/mol, one could assume the volume of the solution is just 200 mL (0.200 L) as no volume change is observed when mixing, therefore, the molarity results:

M=\frac{n_{solute}}{V_{solution}} =\frac{3.9g*\frac{1mol}{93g} }{0.2L} =2.1x10^{-1}M

Moreover, the molality:

m=\frac{n_{solute}}{m_{solvent}} =\frac{3.9g*\frac{1mol}{93g} }{0.2L*\frac{1.05kg}{1L} } =2.0x10^{-1}m

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