Answer:
C) $5,000
Explanation:
Since the price of the stocks first rose to $50, the account's equity was $50,000.
The SMA balance was = ($50,000 x 1/2) - $20,000 = $,5000
The SMA balance acts like a stabilizer and cannot be taken away even if the price of the stocks fall slightly. The price of stocks must fall 25% in order for the SMA to be withdrawn.
The investor's equity decreased = equity - margin requirement = $39,000 - $20,000 = $19,000, but the amount that the investor can borrow (SMA balance) will remain the same at $5,000.
<span>Market research tells producers what consumers want and what they're willing to pay.
Marketers perform market research so they can accurately determine who their audience is, what people will buy, how much they will buy and how much they will pay for it. Without conducing this research they could be spending money trying to reach the wrong audience. They could also have their product set too high or too low and potentially lose money/customers.
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Answer:
$7.90 per unit
Explanation:
The computation of the minimum price on these defective units is shown below:
It is equivalent to the selling & admin variable cost per unit i.e. $7.90 per unit
oAs all the other cost would be considered as a sunk cost because the product is already generated and the fixed cost is not considered as it would remain the same whether the production is increase or not
Therefore the second option is correct
Given the following parameters:
The employer pays the employee (gross earnings) – $1,200
The employer pays for social security and medicare taxes – $91.80
The employer pays for the Federal
Unemployment Tax Act (FUTA) – $9.60
The employer pays for the State
Unemployment Tax Act (SUTA) – $64.80
The total cost of this employee to the employer is the summation of all these costs
1,200 + 91.80 + 9.60 + 64.80 = $1366.20
Answer:
Option (d) , Bank 4 offers the highest amount after a year
Explanation:
The total amount from each of the interest rates can be expressed as;
A=P(1+r/n)^nt
where;
A=Future value of investment
P=Initial value of investment
r=Annual interest rate
n=Number of times the interest is compounded annually
t=number of years of the investment
a). Bank 1
P=x
r=6.1%=6.1/100=0.061
n=1
t=assume number of years=1
replacing;
A=x(1+0.061/1)^(1×1)
A=x(1.061)
A=1.061 x
b). Bank 2
P=x
r=6%=6/100=0.06
n=12
t=1
Replacing;
A=x(1+0.06/12)^(12×1)
A=x(1.005)^12
A=1.0617 x
c). Bank 3
P=x
r=6%=6/100=0.06
n=1
t=1
Replacing;
A=x(1+0.06/1)^(1)
A=1.0600 x
d). Bank 4
P=x
r=6%=6/100=0.06
n=4
t=1
A=x(1+0.06/4)^(4×1)
A=x(1+0.015)^4
A=x(1.061)
A=1.0614 x
e). Bank 5
P=x
r=6%=6/100=0.06
n=365
t=1
A=x(1+0.06/365)^(365×1)
A=1.0618
Option (d) , Bank 4 offers the highest amount after a year
