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sveta [45]
3 years ago
7

What is the empirical formula

Chemistry
1 answer:
lord [1]3 years ago
5 0

A formula giving the proportions of the elements present in a compound but not the actual numbers or arrangement of atoms.

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Look at the two question marks between zinc (zn) and arsenic (as). at the time, no elements were known with atomic weights betwe
Thepotemich [5.8K]

<u>Mendeleev </u><u>positioned elements in the periodic table in</u><u> increasing order </u><u>of their atomic numbers, such that </u><u>elements </u><u>having identical chemical properties and characteristics plunge into the </u><u>same group.</u>

What is Mendeleev's periodic table called?

  • In order to represent similarities and patterns in the behavior of elements, Mendeleev created the periodic table, which is an arrangement of elements in an increasing atomic mass order in tablet form.
  • Mendeleev stated that "Element characteristics are a periodic function of their atomic weight" in his renowned periodic law.
  • The Periodic Table of Mendeleev is a table that Mendeleev created to list elements in the order of their atomic weights.

  • Mendeleev discovered that there were two elements with atomic weights between 65.2 and 75 because he found it very satisfying that the properties of the elements were more similar and closer to this level.
  • He also imagined having other elements with possessions similar to those of these other elements.
  • In the periodic table, he left a blank for these two elements until they were finally discovered in their true existence.

Learn more about Mendeleev's periodic table

brainly.com/question/11974961

#SPJ4

3 0
1 year ago
What is the mole fraction of each component if 3.9 g of benzene (C6H6) is dissolved in 4.6 g of toluene (C7H8)
Savatey [412]

Answer:

Step 1 of 6

(a)

The mass of benzene is  , so calculate the moles of benzene as follows:



The mass of toluene is, so calculate the moles of toluene as follows:



Now, calculate the mole fraction as follows:





Therefore, the mole fraction of benzene and toluene is  and  respectively.

Step 2 of 6

(b)

The formula to calculate the partial pressure is as follows:



Here,  is the partial pressure of benzene,  is the vapour pressure of pure benzene and  is the mole fraction of benzene.

Vapour pressure of pure benzene at  is.

Substitute the values in the equation as follows:



Therefore, the partial pressure is  .

Step 3 of 6

(c)

Vapor pressure of the solution at 1 atm is  .

When the total pressure of the vapour pressure of the mixture is  at a temperature, then, the solution boils. It corresponds to the boiling point of the solution.

Calculate the total pressure of the solution at  as follows:



Since, the total pressure is less than the atmospheric pressure, the solution will not boil at  .

Calculate the total pressure of the solution at  as follows:



Since, the total pressure is greater than the atmospheric pressure, the solution will boil at  .

Therefore, the boiling point of the solution is  .

Step 4 of 6

(d)

Mole fraction of benzene at  is calculated as follows:



Mole fraction of toluene at  is calculated as follows:



Therefore, the mole fractions of benzene and toluene are  and  respectively.

Step 5 of 6

(e)

Vapor pressure of benzene at  is  .

Partial pressure of benzene is calculated as follows:



Vapor pressure of toluene at  is  .

Partial pressure of toluene is calculated as follows:



Step 6 of 6

Weight composition of the vapour that is in equilibrium with the solution is calculated as follows:



Weight composition of the vapour that is in equilibrium with the solution is calculated as follows:



Explanation:

mark me as brainliest

4 0
3 years ago
Read 2 more answers
You have prepared a 1.0 M solution of CaCl2 in the laboratory.
Ratling [72]
It’s C I think and I’m not sure
6 0
3 years ago
How would one convert 6 pounds to ounces (16 oz = 1b)?
NNADVOKAT [17]

Answer:

D.

Explanation:

I just got it right in the test :)

6 0
3 years ago
5 drops of 0.15 M Ki added to<br>40 drops of Na2S2O3<br>What is the final concentration of ki?​
rjkz [21]

Answer:

\boxed{\text{0.017 mol/L}}

Explanation:

Na₂S₂O₃ solution does not react with KI (it reacts with I₂), so it is simply diluting the KI, and we can use the dilution formula.

c_{1}V_{1} = c_{2}V_{2}

Data:

c₁ = 0.15 mol·L⁻¹; V₁ = 5 drops

V(Na₂S₂O₃) = 40 drops

Calculations:

(a) Calculate the total volume

V₂ = 5 + 40 = 45 drops

(b) Calculate the concentration

0.15 × 5 = c₂ × 45

0.75 = 45c₂

c_{2} = \dfrac{0.75 }{45} = \boxed{\textbf{0.017 mol/L}}

3 0
3 years ago
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