Cierto elemento presenta dos isótopos cuyos números de masa suman 110 y cuyos números de neutrones suman 58 ¿Cuál es el número a
1 answer:
You might be interested in
<u>Answer:</u> The value of is 0.044
<u>Explanation:</u>
We are given:
Initial moles of methane =
Initial moles of carbon tetrachloride =
Volume of the container = 1.00 L
Concentration of a substance is calculated by:
So, concentration of methane =
Concentration of carbon tetrachloride =
The given chemical equation follows:
<u>Initial:</u> 0.0410 0.0651
<u>At eqllm:</u> 0.0410-x 0.0651-x 2x
We are given:
Equilibrium concentration of carbon tetrachloride =
Evaluating the value of 'x', we get:
Now, equilibrium concentration of methane =
Equilibrium concentration of
The expression of for the above reaction follows:
Putting values in above expression, we get:
Hence, the value of is 0.044
Answer:
The precipitate was chromium hydroxide, which then reacted with more hydroxide to produce a soluble complex, Cr(OH)4
Explanation:
The following reaction takes place when chromium(III) nitrate reacts with NaOH:
+3 NaOH →
(s)+
The precipitate that is formed is chromium hydroxide,
When more NaOH is added, the precipitate reacts with it which then results in the formation of a soluble complex ion:
(s) +
(aq) →
(aq)
is soluble complex ion