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4 years ago

Exercise can help prevent?

Physics

2 answers:

Sedaia [141]4 years ago

8 0

health conditions and diseases

Tcecarenko [31]4 years ago

4 0

Heart problems? Weight gain? Health conditions & disease?

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Janet wants to find the spring constant of a given spring, so she hangs the spring vertically and attaches a 0.61 kg mass to the

svet-max [94.6K]

Given: Mass m = 0.61 Kg; Displacement x = 4.0 cm or x = 0.04 m

Required: Spring constant k = ?

Formula: F = kx

k = F/x

k = (0.61 Kg)(9.8 m/s²)/0.04 m

k = 149.45 N/m

7 0

4 years ago

The difference between an innate behavior and a learned behavior is that a learned behavior is __________ and an innate behavior

lukranit [14]

ANSWER:

D. A result of experience.

The difference between an innate behaviour and learned behaviour is that a learned behaviour is a result of experience and an innate behaviour is not.

4 0

4 years ago

Read 2 more answers

A satellite is in a circular orbit around the Earth at an altitude of 2.80 3 106 m. Find (a) the period of the orbit, (b) the sp

Katen [24]

Explanation:

Given that,

Altitude $h= 2.803\times10^{6}\ m$

We need to calculate the radius

$r=R+h$

Where, R = radius of the earth

h = radius of altitude

Put the value into the formula

$r=(6.38\times10^{6}+2.803\times10^{6})$

$r=9.18\times10^{6}\ m$

(a). We need to calculate the period of the orbit,

Using formula of period

$T^2=\dfrac{4\pi^2}{GM}r^3$

$T^2=\dfrac{4\pi^2}{6.67\times10^{-11}\times5.98\times10^{24}}\times(9.18\times10^{6})^3$

$T^2=76570372.9509\ sec$

$T=8750.45\ sec$

(b). We need to calculate the speed of the satellite

Using formula of speed

$v^2=\dfrac{GM}{r}$

Put the value into the formula

$v^2=\dfrac{6.67\times10^{-11}\times5.98\times10^{24}}{9.18\times10^{6}}$

$v^2=43449455.3377\ m/s$

$v=6.59\times10^{3}\ m/s$

(c). We need to calculate the acceleration of the satellite

Using formula of acceleration

$a_{c}=\dfrac{v^2}{r}$

Put the value into the formula

$a_{c}=\dfrac{(6.59\times10^{3})^2}{9.18\times10^{6}}$

$a_{c}=4.73\ m/s^2$

Hence, This is the required solution.

6 0

4 years ago

As a train accelerates uniformly, it passes successive 5-kilometer markers while traveling at velocities 10 m/s and 25 m/s. what

gregori [183]

<span>122.0 km/hr. First letâ€™s make sure all of our units are in the base meter form: i.e. convert 5km to 5000m. (We will convert back to km later). The first thing to do is look at the equation relating velocity, acceleration, and distance: Vf^2 = Vi^2 + 2*a*d, where Vf is final velocity, Vi is initial velocity, a is acceleration, and d is distance. 25^2 = 10^2 + 2*a*5000 =?> 625 = 100 +10000a => a= 0.0525m/s^2. Now that we have acceleration, we can use the same equation again with different numbers.: Vf^2 = Vi^2 + 2*a*d = 25^2 + 2*0. 0525m*5000 = 625 + 525 =1150 => Vf^2 = 1150 => 33.9m/s. Convert to km/hour: 33.9m/s * 1km/1000m *60s/1min * 60min/ 1 hr = 122.0 km/hr.</span>

8 0

4 years ago

Rooted plants are most likely found in which aquatic zone?

Mnenie [13.5K]

Ans. Littoral zone.

Littoral zone can be defined as the area of a rive, sea, or lake, which lies close to the shore. It is characterized by abundant sunlight, dissolved oxygen, nutrients, and high water motion. These characteristics make it suitable for marine life. Hence, littoral zone is enriched with various plants and animal species, and coral reefs.

3 0

3 years ago