Explanation:
I'd love to but we cant talk right now cause its 12:22 am here and I'm gonna sleep now lol.
but let's follow each other.
who knows we might be able to help each other.
whaddya say?
have a good day ♡
Answer:
Power of the string wave will be equal to 5.464 watt
Explanation:
We have given mass per unit length is 0.050 kg/m
Tension in the string T = 60 N
Amplitude of the wave A = 5 cm = 0.05 m
Frequency f = 8 Hz
So angular frequency ![\omega =2\pi f=2\times 3.14\times 8=50.24rad/sec](https://tex.z-dn.net/?f=%5Comega%20%3D2%5Cpi%20f%3D2%5Ctimes%203.14%5Ctimes%208%3D50.24rad%2Fsec)
Velocity of the string wave is equal to ![v=\sqrt{\frac{T}{\mu }}=\sqrt{\frac{60}{0.050}}=34.641m/sec](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cfrac%7BT%7D%7B%5Cmu%20%7D%7D%3D%5Csqrt%7B%5Cfrac%7B60%7D%7B0.050%7D%7D%3D34.641m%2Fsec)
Power of wave propagation is equal to ![P=\frac{1}{2}\mu \omega ^2vA^2=\frac{1}{2}\times 0.050\times 50.24^2\times 34.641\times 0.05^2=5.464watt](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B1%7D%7B2%7D%5Cmu%20%5Comega%20%5E2vA%5E2%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%200.050%5Ctimes%2050.24%5E2%5Ctimes%2034.641%5Ctimes%200.05%5E2%3D5.464watt)
So power of the wave will be equal to 5.464 watt
The question here would be what is the volume of the room. The density of air that is given has no use. We simply multiply the dimensions given of the room to determine the volume.
<span>43.0m × 18.0m × 15.0m = 11610m^3 ( 3.28 ft / 1 m)^3 = 4.09 x 10^5 ft^3</span>
The answer is D. I hope this helps