Answer:
A stone on the ground does not have zero energy…there is an internal potential in every object. Aldo is not in action or in any mechanical motion it is being acted upon by gravity and also molecular forces and energy.
<em>Hope</em><em> </em><em>this</em><em> helps</em><em> </em><em>!</em>
Answer
given,
mass of satellite = 2400 Kg
speed of the satellite = 6.67 x 10³ m/s
acceleration of satellite = ?
gravitational force of the satellite will be equal to the centripetal force
Assuming the radius of circular orbit = 8.92 x 10⁶ m
now,
F = 11970.11 N
acceleration,
a = 4.98 m/s²
Answer:
368224.29906 m/s
Explanation:
M = Mass of Polonium nucleus = 214 u
V = Velocity of nucleus
m = Mass of Helium nucleus = 4 u
v = Velocity of alpha particle = 
In this system the momentum is conserved
The recoil speed of the nucleus that remains after the decay is 368224.29906 m/s
This is because the pressure is so much larger at 3000 meters than it is at sea level. Hope this helps.
Explanation:
This problem bothers elastic collision.
Given data
Mass m1= 25kg
Initial velocity u1= 5m/s
Final velocity v1= 1.5m/s
Mass m2= 35kg
Initial velocity u2=?
Final velocity v2 = 4.5m/s
A. To find the initial velocity of the 35kg car, let us Apply the principle of conservation of energy
m1u1+m2u2= m1v1+m2v2
25*5+ 35*u2= 25*1.5+ 35*4.5
125+35u2= 37.5+157.5
125+35u2=195
35u2= 195-125
35u2= 70
u2= 2m/s
The initial velocity is 2m/s
B. Totally not kinetic energy before impact
KE= 1/2m1u1²+ 1/2m2u2²
KE= (25*5²)/2+ (35*2²)/2
KE= 625/2 +140/2
KE= 312.5+70
KE= 382.5J
Total kinetic energy after impact
KE=1/2m1v1²+ 1/2m2v2²
KE= (25*1.5²)/2 +(35*4.5²)/2
KE= 56.25/2 +708.75/2
KE=28.125 +354.375
KE= 382.5J
We can see that energy is conserved
Kinetic energy before and after impact remains unchanged
