Answer:
a) 16.4 m/s
b) 16.4 m/s
c) 16.4 m/s
Explanation:
a)
m = mass of the snowball = 0.690 kg
h = height of the cliff = 8.25 m
v₀ = initial speed of ball at the time of launch = 10.3 m/s
v = speed of the ball as it reach the ground
Using conservation of energy
initial kinetic energy + initial potential energy at the cliff = final kinetic energy just before reaching the ground
(0.5) m v₀² + mgh = (0.5) m v²
(0.5) v₀² + gh = (0.5) v²
(0.5) (10.3)² + (9.8 x 8.25) = (0.5) v²
v = 16.4 m/s
b)
As the launch angle is changed, the speed of the ball just before reaching the ground remain the same as the final speed does not depend on the angle of launch.
v = 16.4 m/s
c)
As the mass is changed, the speed of the ball just before reaching the ground remain the same as the final speed does not depend on the mass of the ball.
v = 16.4 m/s
Answer:
Explanation:
Formula for intensity of light after transmission for unpolarised light is
I₀ / 2 , We shall take up 180 degree disk first .
For second transmission , the formula is
I = I₀ Cos²θ , θ is angle between axis of polarizer and axis of vibration.
If we take up 30 degree polariser
I = I₀ / 2 Cos²( 180 - 30 )
= .375 I₀
For third transmission
I_ final = .375 I₀ x cos( 90 - 30 )
= .1875 I₀
Final/I₀ = .1875
Answer:
Kindly check explanation
Explanation:
Length of race = 5km
Maximum speed = 45 yards
Converting from yards to kilometer :
1km = 1093.613 yards
x = 45 yards
(1093.613 * x) = 45
x = 45 / 1093.613
x = 0.0411480 km
Where x = maximum length for which he can maintain his maximum speed expressed in kilometers.
Therefore, with the available information, it can be concluded that Lamar cannot maintain his maximum speed for the entire 5km race and will only be able maintain his maximum speed for 0.0411 kilometers.
Answer:
Between 0 and 1 seconds (B)
Explanation:
The velocity of the car over time is represented by the line graphed here
the steeper the line, the greater change in velocity that occurred in a given time frame.
The steepest portion of the line is between 0-1 seconds, which means that the greatest rate of change occurred between 0-1 seconds.
(acceleration is the rate of change)
For a certain interval of time, an object is acted on by a constant non-zero force. For this interval of time . . . . .
A. The object is at rest. No. From F=ma, if F is not zero, the object can't remain at rest.
<em>B.</em> <em>The object's velocity changes.</em> <em>Yes.</em> From F=ma, if F is not zero, there must be acceleration.
C. The object's velocity can only increase. No. It might decrease.
D. The object is moving with constant velocity. No. From F=ma, if F is not zero, there must be acceleration.
<em>E.</em> <em>The object is accelerating.</em> <em>Yes.</em> From F=ma, if F is not zero, there must be acceleration.
