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Mekhanik [1.2K]
3 years ago
8

Solar evaporation ponds are shallow so that the sun can heat them up, causing the water to evaporate, which increases the salt c

oncentration. A hybrid of which two bacteria tested in this lab would find life in this habitat ideal?
Physics
1 answer:
ehidna [41]3 years ago
6 0

Answer:

B. stearothermophilus and S. ruber

Explanation:

B. stearothermophilus and S. ruber

In solar evaporation ponds the temperature is higher and the salt concentration is also higher because of the water evaporated so sunder such extreme conditions this hybrid bacteria is capable of surviving. B. stearothermophilus is thermophilus bacteria which grows at high temperature and S. ruber is halophilic bacteria which grows in saline environment. So, these two bacteria best suited for the above hybrid condition.

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The forklift exerts a 1,500.0 N force on the box and moves it 3.00 m forward to the stack. How much work does the forklift do ag
allochka39001 [22]
In order to get the propoerty of work you need to use the following formula
 <span>work = force times distance
</span>replacing data you will get:
W = (1.500) (3)
W =  4.500 NM
The answer should be in NM. So it will be 4500 NM againts the force of gravity
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3 years ago
What is the answer of A and B question 2
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3 years ago
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A reconnaissance plane flies 560 km away from its base at 602 m/s, then flies back to its base at 903 m/s.
IrinaVladis [17]

Answer:

Approximately 722\; \rm m\cdot s^{-1}.

Explanation:

The average speed of a vehicle is calculated as:

\displaystyle \text{average speed} = \frac{\text{total distance}}{\text{total time}}.

In this question, the total distance is 2 \times 560\; \rm km = 1120\; \rm km.

The unit of the speeds in this question is meters per second, while the unit of distance is kilometers. Convert the unit of distance to meters:

560 \; \rm km = 560 \times 10^{3} \; \rm m = 5.6 \times 10^{5}\; \rm m.

1120 \; \rm km = 1120 \times 10^{3} \; \rm m = 1.12 \times 10^{6}\; \rm m.

Time required for the first part of this trip:

\displaystyle \frac{5.60 \times 10^{5}\; \rm m}{602\; \rm m\cdot s^{-1}} \approx 930\; \rm s.

Time required for the second part of this trip:

\displaystyle \frac{5.60 \times 10^{5}\; \rm m}{903\; \rm m\cdot s^{-1}} \approx 620\; \rm s.

The time required for the entire trip would be approximately 930 + 620 = 1550\; \rm s.

Calculate the average speed of this plane:

\begin{aligned} \text{average speed} &= \frac{\text{total distance}}{\text{total time}} \\ &\approx \frac{1.12\times 10^{6}\; \rm m}{1550\; \rm s} \approx 722\; \rm m \cdot s^{-1}\end{aligned}.

6 0
2 years ago
If the radius of the sun is 7.001×105 km, what is the average density of the sun in units of grams per cubic centimeter? The vol
xenn [34]

Answer:

Average density of Sun is 1.3927 \frac{g}{cm}.

Given:

Radius of Sun = 7.001 ×10^{5} km = 7.001 ×10^{10} cm

Mass of Sun = 2 × 10^{30} kg = 2 × 10^{33} g

To find:

Average density of Sun = ?

Formula used:

Density of Sun = \frac{Mass of Sun}{Volume of Sun}

Solution:

Density of Sun is given by,

Density of Sun = \frac{Mass of Sun}{Volume of Sun}

Volume of Sun = \frac{4}{3} \pi r^{3}

Volume of Sun = \frac{4}{3} \times 3.14 \times [7.001 \times 10^{10}]^{3}

Volume of Sun = 1.436 × 10^{33} cm^{3}

Density of Sun = \frac{ 2\times 10^{33} }{1.436 \times 10^{33} }

Density of Sun = 1.3927 \frac{g}{cm}

Thus, Average density of Sun is 1.3927 \frac{g}{cm}.

4 0
3 years ago
Which statements correctly describe the formula or name of a compound? Select all that apply.
PtichkaEL [24]

Answer:

The formula of nitrogen trifluoride is NF 3

The formula of ammonia is NH3

The formula of magnesium hydroxide is Mg(OH)2

Explanation:

The formula of a compound refers to the correct representation of the compound using appropriate chemical symbols.

The formula of a compound is derived from the symbols of its constituent elements. The formula of the compound must correctly show the number of atoms of each element in one formula unit of the compound.

In the answer section, the correct names or formulas of some compounds have been shown

8 0
3 years ago
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