Complete Question
A student bikes to school by traveling first dN = 0.900 miles north, then dW = 0.300 miles west, and finally dS = 0.100 miles south.
Similarly, let d⃗ W be the displacement vector corresponding to the second leg of the student's trip. Express d⃗ W in component form.
Express your answer as two numbers separated by a comma. Be careful with your signs.
Answer:
The value is 
Explanation:
From the question we are told that
The first displacement is 
i.e positive y-axis
The second displacement is 
i.e negative x-axis
The final displacement is 
i.e negative y-axis
Generally dW in component for is
Generally the total displacement of the student is mathematically represented as
Answer:
Effective Pulling Force = 29.2(cos 62.7°) = 13.393 N
Resistance to Pulling Force = 11.7 N
Net Force acting on suitcase = 13.393 - 11.7 = 1.693 N
Distance moved = 8.44 m
Net Work = 1.693(8.44) = 14.289 ≈ 14.3 J ANS
Explanation:
hope that makes sense homie
to make sure the argument is true and correct backed up by logic.
(i)1.5cm
(ii)4.5cm
(iii)10cm
Answer:
337k
Explanation:
First, let us find the difference between the given two temperatures.
Difference = 85°C - 21°C
= 64°C
<u>And now we have to write the temperature in kelvins.</u>
To convert Celcius to Kelvins you can add 273 to the temperature in Celcius.
<u>Let us find it now.</u>
64°C + 273 = 337k
Therefore,
64°C ⇒ <u>337k</u>
