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Alex777 [14]
3 years ago
12

A bee flies at a constant rate of 5 m s until it notices a flower. It then comes to rest in 5 seconds. Find the acceleration of

the bee if a= ?v ?t . A) -5 m s2 B) -1 m s2 C) 1 m s2 D) 5 m s2
Physics
1 answer:
FrozenT [24]3 years ago
5 0

Answer:

B) -1m/s^2

Explanation:

Final speed = 0 m/s

Initial speed = 5m/s

Time taken for it to come to rest(0m/s) = 5

then use the formula;

[v = u + at],where v is the final speed..u is the initial speed..t is time taken for it to come to rest and a is the acceleration

; 0 = 5 + 5a

; -5 = 5a

;Acceleration = -1 m/s^2

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luda_lava [24]
What was the answer?

8 0
3 years ago
A tennis ball is thrown vertically upward with an initial velocity of +6.2 m/s. What will the ball’s velocity be when it returns
anastassius [24]

Answer:

v_{f}=-6.2 m/s

Explanation:

The ball will rise decreasing its speed until it reaches the highest point where its speed will be zero. From this point the tennis ball will begin to fall again, in the free fall the tennis ball will gain speed but now in the opposite direction. When it returns to the same point where it was launched, its speed will be the same as the one that was launched but with the opposite sign.

v_{f}=-6.2 m/s

We can check this using the equation:

v_{f}^2=v_{i}^2+2gh

where v_{i}=+6.2 m/s

ang h is the height, but because the ball returns to the same point where it started, h =0

then

v_{f}^2=v_{i}^2

v_{f}=v_{i}

the initial and final velocity will be the same in number, but we know that the ball is going in the opposite direction, so the final velocity must have the opposite sign from the initial velocity

so if v_{i}=+6.2 m/s,

v_{f}=-6.2 m/s

4 0
3 years ago
Light in a vacuum travels at a constant speed of 3x10^8 m/s. If the moons average distance from the earth is 38776106 km how lon
Karo-lina-s [1.5K]

Answer: 258.3 s

Explanation:

The speed s is given by the following equation:

s=\frac{D}{t}

Where:

s=3(10)^{8} m/s is the speed of light in vacuum

D=2(38776106 km \frac{1000 m}{1 km})=7.75(10)^{10} m is the double of the distance between Earth and Moon, since the beam of light travels from Earth to the Moon and back to Earth again.

t is the time it takes to the beam of light to travel the mentioned distance

Isolating t and solving with the given information:

t=\frac{D}{s}

t=\frac{7.75(10)^{10} m}{3(10)^{8} m/s}

Finally:

t=258.3 s \approx 258 s

5 0
3 years ago
Help me pls, I need it now​
posledela

6.) a

7.) d

8.) b

9.) b

10.) a

3 0
2 years ago
What is the momentum of a 10.5 kg rolling at 3 m/s
timurjin [86]
Momentum = mass x velocity
Momentum = 10.5 x 3
Momentum = 31.5 kgm/s
6 0
3 years ago
Read 2 more answers
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