The distance of tiger's leap from the base of rock is 5.58 m
It is a question of two dimensional motion
The time of motion in two dimensional motion is given by:
t=
where y is the height and g is the acceleration due to gravity
y is given to be 7.5m and let us assume g to be 9.8 m/s^2
t =
= 1.24s
Using time and speed,
We know that distance is the product of speed and time,
Distance= speed x time
speed is given to be 4.5 m/s
distance from the base of rock = 4.5 x 1.24
= 5.58m
Hence the distance of tiger's leap from the base of rock is 5.58 m
Disclaimer:
The acceleration due to gravity is assumed to be 9.8 m/s^2
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To develop this problem, it is necessary to apply the concepts related to Faraday's law and Magnetic Flow, which is defined as the change that the magnetic field has in a given area. In other words
Where
B= Magnetic Field
A = Area
Angle between magnetic field lines and normal to the area
The differentiation of this value allows us to obtain in turn the induced emf or electromotive force.
In this case we have that the flat loop of wire is perpendicular to the magnetic field, therefore the angle is 0 degrees, since its magnetic field acts parallel to the area:
0 then our expression can be written as
From the same value of the electromotive force we have to
Replacing we have
Replacing with our values we have that
Therefore the magnitude of the induced emf in the loop is 0.0237V
On the other hand we have that the current by Ohm's Law can be defined as
For the given value of the resistance and the previously found potential we have to
Since we’re going east then, you should added double 300 so that makes your answer 600m.
Answer:
2.726472 s more or 1.5874 times more time is taken than 10-lb roast.
Explanation:
Given:
- The cooking time t is related the mass of food m by:
t = m^(2/3)
- Mass of roast 1 m_1 = 20 lb
- Mass of roast 2 m_2 = 10 lb
Find:
how much longer does a 20-lb roast take than a 10-lb roast?
Solution:
- Compute the times for individual roasts using the given relation:
t_1 = (20)^(2/3) = 7.36806 s
t_2 = (10)^(2/3) = 4.641588 s
- Now take a ration of t_1 to t_2, to see how many times more time is taken by massive roast:
t_1 / t_2 = (20 / 10)^(2/3)
- Compute: t_1 / t_2 = 2^(2/3) = 1.5874 s
- Hence, a 20-lb roast takes 1.5874 times more seconds than 10- lb roast.
t_2 - t_1 = 2.726472 s more