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VMariaS [17]
3 years ago
13

Please help with this conversion question about heat! WILL MARK BRAINLIEST!!!

Physics
2 answers:
Whitepunk [10]3 years ago
7 0

The first group, right under the "Which ...", are all the same temperature.

Alexxx [7]3 years ago
5 0

The first answer.

100 Celsius = 373.15 Kelvin

100 Celsius = 212 Fahrenheit

So:

373 Kelvin, 100 degrees Celsius, 212 degrees Fahrenheit.

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A car collides into a concrete wall going 25.0 m/s . It stops in 0.141 seconds and has a change in momentum of 39,400. What is t
vodka [1.7K]

Answer:

Mass of the car is 1576 kg.

Explanation:

Let the mass of the car be m kg.

Given:

Initial velocity of the car is, u=25\ m/s

As the car stops, final velocity of the car is, v=0\ m/s

Change in momentum is, \Delta p=39400

Now, we know that, momentum is given as the product of mass and velocity.

So, change in momentum is given as:

\Delta p=m(u-v)\\39400=m(25-0)\\39400=25m\\m=\frac{39400}{25}\\m=1576\ kg

Therefore, the mass of the car is 1576 kg.

4 0
3 years ago
Why is it important to know the location of active and inactive faults in our country?
Andrew [12]

Answer:

I hope this helps.

Explanation:

It's important to know the location of an active fault in order to determine the magnitude of the expected earthquake. There is a chance than an inactive fault can become active again. It's important that we take the locations into account in order to be prepared and ready for if it occurs.

5 0
3 years ago
A 150 g sample of brass at 100 °C is placed in a Styrofoam cup of water containing 120 mL of water at 10 °C. No heat is lost to
fredd [130]

Answer:

≈19.144°C.

Explanation:

all the details are in the attachment.

Note, that c₁, m₁, t₁ are the parameters of the sample of brass; c₂, m₂ and t₂ are  the parameters of the sample of water.

P.S. change the provided design according Your requirements.

4 0
2 years ago
What is the net force on a car if the force of friction is 15 N and the forward force due to the engine is 20 N?
anygoal [31]
D. 35n forwards....................
8 0
3 years ago
An object, with a final position of x = 100.1 meters, initially started at x = -12.13 meters. What was its displacement? (Unit =
nikklg [1K]

Answer:

112.23 m

Explanation:

Displacement is the final position minus the initial position.

Δx = x − x₀

Δx = 100.1 m − (-12.13 m)

Δx = 112.23 m

8 0
3 years ago
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