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VMariaS [17]
3 years ago
13

Please help with this conversion question about heat! WILL MARK BRAINLIEST!!!

Physics
2 answers:
Whitepunk [10]3 years ago
7 0

The first group, right under the "Which ...", are all the same temperature.

Alexxx [7]3 years ago
5 0

The first answer.

100 Celsius = 373.15 Kelvin

100 Celsius = 212 Fahrenheit

So:

373 Kelvin, 100 degrees Celsius, 212 degrees Fahrenheit.

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Tension: tension = Te/J = 2T/ piC^3

= (2)(2500)/pi (0.0625)^3 = 6.519 x 10^3 psi = 6.519 ksi

 

Bending:

I = pi/4 * c^4 = 119.842 x 10^-3 in^4

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Gx = -18.775 ksi

Gy = 0

Txy = 6.519 ksi

 

G ave – ½ (Gx + Gy) = -9.387 ksi
R = sqrt (Gx – Gy/2)^2 + Txy^2 = sqrt(-9.387)^2 + (6.519)^2 = 11.429 ksi

 

1.       G1 = Gave + R = -9/387 + 11.429 = 2.04 ksi

G2 = Gave - R = -9/387 - 11.429 = -20.8

 

Tan 2ϴp = 2txy/Gx – Gy = 2(6.519)/-9.387 = -1.3889

ϴp = -27.1 degrees and 62.9 degrees

 

 

2.       Tmax = R = 11.43 ksi

R = sqrt (Gx – Gy/2)^2 + Txy^2 = sqrt(-9.387)^2 + (6.519)^2 = 11.429 ksi

<span> </span>

3 0
3 years ago
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