Answer:
2 x 10^-8
Explanation:
the formula of wavelength is
the speed divided by frequency
so you have the speed given = 3.0x10^8m/s
and frequency = 1.5×10^16 Hz
so wavelength = 3.0x10^8m/s / 1.5x10^16 Hz
Answer:
28,400 N
Explanation:
Let's start by calculating the pressure that acts on the upper surface of the hatch. It is given by the sum of the atmospheric pressure and the pressure due to the columb of water, which is given by Stevin's law:
![p_{top} = p_{atm} + \rho g h=1.013\cdot 10^5 Pa + (1000 kg/m^3)(9.8 m/s^2)(21.0 m)=3.071 \cdot 10^5 Pa](https://tex.z-dn.net/?f=p_%7Btop%7D%20%3D%20p_%7Batm%7D%20%2B%20%5Crho%20g%20h%3D1.013%5Ccdot%2010%5E5%20Pa%20%2B%20%281000%20kg%2Fm%5E3%29%289.8%20m%2Fs%5E2%29%2821.0%20m%29%3D3.071%20%5Ccdot%2010%5E5%20Pa)
On the lower part of the hatch, there is a pressure equal to
![p_{bot}=p_{atm}=1.013\cdot 10^5 Pa](https://tex.z-dn.net/?f=p_%7Bbot%7D%3Dp_%7Batm%7D%3D1.013%5Ccdot%2010%5E5%20Pa)
So, the net pressure acting on the hatch is
![p=p_{top}-p_{bot}=3.071 \cdot 10^5 Pa - 1.013\cdot 10^5 Pa=2.058 \cdot 10^5 Pa](https://tex.z-dn.net/?f=p%3Dp_%7Btop%7D-p_%7Bbot%7D%3D3.071%20%5Ccdot%2010%5E5%20Pa%20-%201.013%5Ccdot%2010%5E5%20Pa%3D2.058%20%5Ccdot%2010%5E5%20Pa)
which acts from above.
The area of the hatch is given by:
![A=\pi r^2 = \pi (\frac{0.420 m}{2})^2=0.138 m^2](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E2%20%3D%20%5Cpi%20%28%5Cfrac%7B0.420%20m%7D%7B2%7D%29%5E2%3D0.138%20m%5E2)
So, the force needed to open the hatch from the inside is equal to the pressure multiplied by the area of the hatch:
![F=pA=(2.058\cdot 10^5 Pa)(0.138 m^2)=28,400 N](https://tex.z-dn.net/?f=F%3DpA%3D%282.058%5Ccdot%2010%5E5%20Pa%29%280.138%20m%5E2%29%3D28%2C400%20N)
Answer:
Up first are Mercury and Venus. Neither of them has a moon. Because Mercury is so close to the Sun and its gravity, it wouldn't be able to hold on to its own moon. Any moon would most likely crash into Mercury or maybe go into orbit around the Sun and eventually get pulled into it.
I'd say diffraction since sound waves can bend around objects like corners. Let's say you're in the hallway and you can hear sound coming from a door. The sound waves diffract around the door and spread out into the hallway, making it possible for you to hear.
Also, you can hear it before you see it because light waves are shorter than sound waves and hardly diffract around doors.
Answer:
Explanation:
Mass of ice m = 500g = .5 kg
Heat required to raise the temperature of ice by 10 degree
= mass of ice x specific heat of ice x change in temperature
= .5 x 2093 x 10 J
10465 J
Heat required to melt the ice
= mass of ice x latent heat
0.5 x 334 x 10³ J
167000 J
Heat required to raise its temperature to 18 degree
= mass x specific heat of water x rise in temperature
= .5 x 4182 x 18
=37638 J
Total heat
=10465 +167000+ 37638
=215103 J