How are microchips made?

Chemistry

2 answers:

Cerrena [4.2K]3 years ago

6 0

Building up by building up electronic circuits

kolbaska11 [484]3 years ago

5 0

One small plate lolllll sorry

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What is the smallest unit that makes up matter? A. molecules B. chemicals C. atoms D. alloys

Kamila [148]

Hello there!

An Atom would be considered to be the smallest unit that would make up matter. If were to ever see a picture of an atom, they would consists of a proton, neutron, electron, and a nucleus. And all this would be called a Atom.

Your answer: Atom

7 0

3 years ago

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Which option is an element <br> A: carbon dioxide <br> B: Water <br> C: Air<br> D: Carbon

Ivenika [448]

Answer:

D: Carbon

Explanation:

The periodic table lists all the known elements. When looking at it, the only choice you will find is carbon. Therefore, carbon is the element.

Carbon is also by itself, just C.

Water is H2O, which is a molecule due to the 2 different elements.

Carbon Dioxide is CO2, which is a molecule due to the 2 different elements.

Air is just a mixture of different gas molecules, so therefore it is not an element.

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3 years ago

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New questionWhat mass of calcium chloride (CaCl₂) would beproduced from the reaction of 125.9 g of hydrochloriacid (HCI) with ex

marshall27 [118]

Answer:

191.6 g of CaCl₂.

Explanation:

What is given?

Mass of HCl = 125.9 g.

Molar mass of CaCl₂ = 110.8 g/mol.

Molar mass of HCl = 36.4 g/mol.

Step-by-step solution:

First, we have to state the chemical equation. Ca(OH)₂ react with HCl to produce CaCl₂:

$Ca(OH)_2+2HCl\rightarrow CaCl_2+2H_2O.$

Now, let's convert 125.9 g of HCl to moles using the given molar mass (remember that the molar mass of a compound can be found using the periodic table). The conversion will look like this:

$125.9\text{ g HCl}\cdot\frac{1\text{ mol HCl}}{36.4\text{ g HCl}}=3.459\text{ moles HCl.}$

Let's find how many moles of CaCl₂ are being produced by 3.459 moles of HCl. You can see in the chemical equation that 2 moles of HCl reacted with excess Ca(OH)₂ produces 1 mol of CaCl₂, so we state a rule of three and the calculation is: