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enot [183]
3 years ago
9

Mr. jones needs 126 pieces of construction paper to do an art project with the students each he has a full pack of 50 sheets of

paper open pack with some more sheets how many more sheets of paper does he need to borrow from the teacher next-door
Mathematics
1 answer:
fredd [130]3 years ago
8 0

Answer:56

Step-by-step explanation:

Because all he has is 50 sheets

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If your balance after 8 years in the bank at a rate of interest of 11%% is 3783193 how much was your original deposit? 29 Origin
Wittaler [7]

Answer:

The original amount deposit is $1641627.68.

Step-by-step explanation:

Given : If your balance after 8 years in the bank at a rate of interest of 11%% is 3783193.

To find : How much was your original deposit?  

Solution :

Applying interest formula,

A=P(1+r)^t

Where, A is the amount i.e. A=$3783193

P is the principal value i.e. the original deposit

r is the interest rate r=11%=0.11

t is the time t=8 years.

Substitute the value in the formula,

3783193=P(1+0.11)^8

3783193=P(1.11)^8

3783193=P\times 2.30

P=\frac{3783193}{2.30}

P=1641627.68

Therefore, The original amount deposit is $1641627.68.

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3 years ago
A bicycle lock requires a two-digit code of numbers 1 through 9, and any digit may be used only once. Which expression would det
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5 0
3 years ago
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How many times longer is the wavelength of a sound wave with a frequency of 20 waves per second than the wavelength of a sound w
sergejj [24]

The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

<h3>Calculating wavelength </h3>

From the question, we are to determine how many times longer is the first sound wave compared to the second sound water

Using the formula,

v = fλ

∴ λ = v/f

Where v is the velocity

f is the frequency

and λ is the wavelength

For the first wave

f = 20 waves/sec

Then,

λ₁ = v/20

For the second wave

f = 16,000 waves/sec

λ₂ = v/16000

Then,

The factor by which the first sound wave is longer than the second sound wave is

λ₁/ λ₂ = (v/20) ÷( v/16000)

= (v/20) × 16000/v)

= 16000/20

= 800

Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

Learn more on Calculating wavelength here: brainly.com/question/16396485

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1 year ago
The difference of 23 and p
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P is a letter and 23 is a number

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