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vaieri [72.5K]
3 years ago
6

Can anyone help me out? :)

Chemistry
1 answer:
andriy [413]3 years ago
6 0

Answer:

the answer is b, there is more than one variable

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If trees loose there leaves as each seasons progress which biome is that
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Temperate Deciduous Fores

Explanation:

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3 years ago
What are the properties of carbon-14?
natali 33 [55]

Answer:

1) Carbon-14 is a naturally occurring carbon isotope.

2) Carbon-14 has a known half-life.

3) Carbon-14 is present in all living organisms.

Living things have carbon-14 in their organism, but when they died, the amount of C-14 they contain begins to decrease as the C-14 undergoes radioactive decay. Measuring the amount of C-14 in a sample from a dead plant or animal when the animal or plant died.

The half-life of C-14 is about 5730 years.

Half-life is the time required for a quantity (in this example number of radioactive nuclei of carbon-14) to reduce to half its initial value.

Hope this helps and also this question was already on Brainly check it out I just copied lol :)

5 0
3 years ago
How many protons does an atom of gold have?
klasskru [66]

Answer:

There are 79 protons in the nucleus of one Gold atom.

Explanation:

The number of protons of any given atom/element can be determined by the atomic number of the specific element, which is found on the periodic table.

3 0
3 years ago
Why does organic chemistry have a wide variety from compounds primarily based on only two elements? please help
andreev551 [17]

Answer:

Explanation:  Organic chemistry have a wide variety from compounds of the presence of two elements namely

  • Carbon
  • Hydrogen

 Organic molecules comprises of multiple chains of carbon atoms with different  lengths and because of the ability of carbon to bond with many elements, This produces  a variety of compounds which no other atom or element can. The main variety of compounds exists in the combination of carbon and hydrogen forming hydrocarbons which are virtuall everywhere around us

4 0
3 years ago
What is the wavelength of an electron with a mass of 9.109×10−31 kg and a velocity of 3.43×107 ms? Use 6.626×10−34kg m2s for Pla
anyanavicka [17]

<u>Answer:</u> The wavelength of an electron is 2.121\times 10^{-11}m

<u>Explanation:</u>

To calculate the wavelength of a particle, we use the equation given by De-Broglie's wavelength, which is:

\lambda=\frac{h}{mv}

where,

\lambda = De-Broglie's wavelength = ?

h = Planck's constant = 6.626\times 10^{-34}Js

m = mass of electron = 9.109\times 10^{-31}kg

v = velocity of electron = 3.43\times 10^{7}m/s

Putting values in above equation, we get:

\lambda=\frac{6.626\times 10^{-34}Js}{(9.109\times 10^{-31}kg)\times (3.43\times 10^{7}m/s)}

\lambda=2.121\times 10^{-11}m

Hence, the wavelength of an electron is 2.121\times 10^{-11}m

6 0
4 years ago
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