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3 years ago

Given the balanced equation representing a reaction:Cl2==> Cl + Cl

1 answer:

4 0

The correct answer is option 1. The balanced reaction represents that a bond is broken and energy is absorbed. Cl2 are held by covalent bonds that are strong. Therefore, energy is required to break these bonds. The energy supplied is absorbed for the reaction to proceed.

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How many nitrogen atoms are present in calcium nitrate, Ca(NO3)2?

bulgar [2K]

There are two atoms of N.

5 0

3 years ago

37.2 moles of hydrogen gas would have what mass?<br> Your answer

raketka [301]

Answer:

74.99g

Explanation:

Mass of a substance can be calculated by using the formula;

mole = mass ÷ molar mass

mass = molar mass × mole

According to this question, 37.2 moles of hydrogen gas is given.

Molar mass of hydrogen gas (H2) = 1.008(2) = 2.016g/mol

mass = 2.016 × 37.2

Mass of H2 = 74.995

Mass = 74.99g

5 0

2 years ago

What is the formula for the compound formed by lead(lV) ions and chromate ions

nexus9112 [7]

Answer:

Lead (IV) Chromate: Pb(CrO4)2

Explanation:

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3 years ago

What type of reaction is <br> CH 4 (g)+2O 2 (g) CO 2 (g)+2H 2 O(g)

tangare [24]

Answer: combustion

Explanation:

Combustion reactions can be identified by looking at the reactants and the products.

Usually, the reactants will be a hydrocarbon and oxygen. And the products will be CO2 and H2O

8 0

3 years ago

A sample of gas initially occupies 4.25 L at a pressure of 0.850 atm at 23.0°C. What will the volume be if the temperature is ch

Akimi4 [234]

Answer:

$2.31\text{ L}$

Explanation:

Here, we want to calculate the final volume

We use the general gas equation here:

$\frac{P_1V_1}{T_1}\text{ = }\frac{P_2V_2}{T_2}$

P1 is the initial pressure which is 0.850 atm

V1 is the initial volume which is 4.25 L

T1 is the initial temperature which is (23 + 273.15 = 296.15 K)

P2 is the final pressure which is 1.50 atm

V2 is the final volume which is unknown

T2 is the final temperature (11.5 + 273.15 = 284.65 K)

Substituting the values, we have:

$\begin{gathered} \frac{0.850\text{ }\times4.25}{296.15}\text{ = }\frac{1.50\times V_2}{284.65} \\ \\ V_2\text{ = }\frac{284.65\text{ }\times0.850\times4.25}{1.5\times296.15} \\ \\ V_2\text{ = 2.31 L} \end{gathered}$

6 0

1 year ago