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stira [4]
3 years ago
13

Given a force of 100 N and an acceleration of 10 m/s2, what is the mass?

Physics
1 answer:
Drupady [299]3 years ago
5 0
F=ma, so 100=m×10. Solve for m by dividing by 10. The mass is 10 kg.
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Using the free-body diagram, calculate the net force
yuradex [85]

Answer:yes it is

Explanation:

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3 years ago
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Suppose we hang a heavy ball with a mass 13 kg (so the weight is ) from a steel wire 3.9 m long that is 3.1 mm in diameter (radi
Katena32 [7]

Answer:

1.635×10^-3m

Explanation:

Young modulus is the ratio of the tensile stress of a material to its tensile strain.

Young modulus = Tensile stress/tensile strain

Tensile stress = Force/Area

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Area = Πr² = Π×(1.55×10^-3)²

Area = 4.87×10^-6m²

Tensile stress = 130/4.87×10^-6 = 8.39×10^7N/m²

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Substituting in the young modulus formula given young modulus to be 2×10¹¹N/m²

2×10¹¹N/m² = 8.39×10^7/{e/3.9)}

2×10¹¹ = (8.39×10^7×3.9)/e

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e = 3.27×10^8/2×10¹¹

e = 1.635×10^-3m

The stretch of the steel wire will be

1.635×10^-3m

7 0
3 years ago
A balloon will stick to a wooden wall if the balloon is charged
grigory [225]
<h2>Answer: either way</h2>

The balloon contains neutral charge atoms, that is, it has the same number of electrons (negative charge), protons (positive charge) and neutrons (no charge).

Then, when two objects come into contact, the electrons of one of them can become part of the other.

Thus, by bringing the balloon closer to the wall, the wall, which is also made up of atoms, will reorder its charges in such a way that its electrons or protons become part of the balloon, charging it.

7 0
3 years ago
Which statement is NOT true?
Nuetrik [128]

Answer:

light doesn't need a medium through which to travel because the speed of light is experimentally constant

4 0
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maria [59]

Answer:

\lambda=1.37\times 10^{-11}\ m

Explanation:

Give that,

The potential difference of the electrons, V=8\times 10^{3}\ V

We need to find the wavelength of the electrons.

Using the conservation of energy,

2meV=\dfrac{h^2}{\lambda^2}\\\\\lambda=\sqrt{\dfrac{h^2}{2meV}}

Put all the values,

\lambda=\sqrt{\dfrac{(6.63\times 10^{-34})^2}{2\times 9.1\times 10^{-31}\times 1.6\times 10^{-19}\times 8\times 10^3}}\\\\\lambda=1.37\times 10^{-11}\ m

So, the wavelength of the electrons is 1.37\times 10^{-11}\ m.

7 0
3 years ago
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