Which characteristics do all terrestrial planets have?

Physics

2 answers:

nignag [31]3 years ago

4 0

Molten Heavy metal core, one to a few moons, valleys, volcanoes, craters.

Vaselesa [24]3 years ago

3 0

Answer:

Composed primarily of silicate rocks or metals
Central metallic core, mostly iron, with a surrounding silicate mantle
Can have canyons, craters, mountains, volcanoes, and other surface structures

Explanation:

We can start saying that a terrestrial planet or telluric planet or rocky planet is kind of planet that is composed primarily of silicate rocks or metals , this the principle characteristic of this planets.

This planets have a solid surface, making them substantially different from the gaseous planets, for instance Jupiter or Saturn, which are composed predominantly of some combination of hydrogen, helium, and water.

All terrestrial planets in the Solar System, for example, have the same basic type of structure, such as a central metallic core, mostly iron, with a surrounding silicate mantle. The Moon in our planet is similar, but has a much smaller iron core, another example of natural satellites are Io and Europa that have internal structures similar to that of terrestrial planets. Also, is important says that terrestrial planets can have canyons, craters, mountains, volcanoes, and other surface structures, depending on the presence of water and tectonic activity.

I hope it helps you!

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6 0

3 years ago

A solid ball and a hollow ball, each with a mass of 1.00 kg and radius of 0.100 m start from rest and roll down a ramp of length

nordsb [41]

Answer:

The solid ball and hollow ball both will reach the bottom with the same speed.

Explanation:

The speed of the solid and hollow balls is independent of the mass and the radius. A solid and hollow ball experience same speed on a given incline.

The speed can be calculated as

v = √(10/7)gh

where g is gravitational acceleration and h is the height

sinθ = h/L

h = L*sinθ

h = 3*sin(35)

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8 0

3 years ago

A flat surface is in a uniform magnetic field. Given only the area of the surface and the magnetic flux through the surface, it

Tasya [4]

Answer:

Given the area A of a flat surface and the magnetic flux through the surface $\Phi$ it is possible to calculate the magnitude $\frac{\Phi}{A}=B\ cos \theta$ .

Explanation:

The magnetic flux gives an idea of how many magnetic field lines are passing through a surface. The SI unit of the magnetic flux $\Phi$ is the weber (Wb), of the magnetic field B is the tesla (T) and of the area A is ( $m^{2}$ ). So 1 Wb=1 T.m².

For a flat surface S of area A in a uniform magnetic field B, with $\theta$ being the angle between the vector normal to the surface S and the direction of the magnetic field B, we define the magnetic flux through the surface as: