Rt c if you were to hit a ping pong ball of mass 0.0029 g with the same force that caused a 0.058-g tennis ball to move with an

Question

3 years ago

8

Rt c if you were to hit a ping pong ball of mass 0.0029 g with the same force that caused a 0.058-g tennis ball to move with an

acceleration of 10 m/s2 , what would the acceleration a of the ping pong ball be? express your answer in meters per second squared.

Physics

2 answers:

kati45 [8] · Answer 1 · 2022-05-30T02:19:12+03:00

F=ma
You know the acceleration and mass of the tennis ball, now you can find the force applied by substituting it into the formula. Also I am assuming you meant to write your units in kg because that seems very light for grams. I am sorry if I misunderstood.
F=ma
= (0.058kg)(10m/s²)
= 0.58N
Now that you know how much force was exerted you can solve for how much acceleration the ping pong ball will have.
F=ma
a=F/m
=(0.58N)/(0.029kg)
=20m/s²
Hope this helps!

Daniel [21] · Answer 2 · 2022-05-30T03:37:13+03:00

<em>The acceleration of the ping pong ball would be </em><em>200 m/s²</em>

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<h3>Further explanation</h3>

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

$\boxed {\Sigma F = ma }$