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JulijaS [17]
3 years ago
11

2. Paraffin and gasoline are both hydrocarbons, and therefore have the same general

Chemistry
1 answer:
leva [86]3 years ago
6 0

Answer:

Paraffin combustion produces more energy per gram than ethanol fuel but paraffin fuel has a larger carbon footprint

Explanation:

Paraffin is also known by the standard chemical name alkane with a chemical formula for a paraffin given as  follows;

CₙH₂ₙ₊₂

While gasoline, also known as petrol, consists of light weight alkanes and alkenes

The heat of combustion of gasoline is about 47.3 kJ/g

The combustion of gasoline is incomplete as presented in the following equation

C_x H_y+ O_2 +N_2 \rightarrow CO_2 + H_2O + CO + HC + NO_x

Example of complete combustion of octane, however, is given as follows;

2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O  + Energy    

The source of paraffin is from petroleum

Ethanol fuel can be produced by the fermentation of Sugar

The heat of combustion of ethanol = 1366.91 kJ/mol = 29.664 kJ/g.

2CH₃OH + 3O₂  → 2CO₂ + 4H₂O  + Energy                              

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Is the equation above balanced or unbalanced? Explain? Worth 55 points.
Paul [167]

Answer:

For me, it is balanced

Explanation:

Because the amount of element Zn reaction is equal the production. Also as the amount of Hydrogen and Chloride in the reaction and the production are equal.

8 0
3 years ago
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What’s the answer for number 2?
Lady bird [3.3K]
The answer to this is surface wave i think
4 0
4 years ago
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3. According to Newton's First Law of Motion, what does an object at rest do?
Taya2010 [7]

Answer:

stays at rest

Explanation:

7 0
3 years ago
Magnesium reacts with Oxygen gas forming Magnesium oxide as shown;
LuckyWell [14K]
Molar mass:

O2 = 16 x 2 = 32.0 g/mol              Mg = 24 g/mol

<span>2 Mg(s) + O2(g) --->2 MgO(s) 
</span>
2 x 24.0 g Mg -------------> 32 g O2
5.00 g Mg -----------------> ( mass of O2)

mass of O2 = 5.00 x 32 / 2 x 24.0

mass of O2 = 160 / 48

= 3.33 g of O2

hope this helps!
5 0
3 years ago
1.
german

Order of metals from least reactive to most reactive: B <C <A <D

<h3>Further explanation</h3>

Reducing agents are substances that experience oxidation  

Oxidizing agents are substances that experience reduction

The metal activity series is expressed in voltaic series  

<em>Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au  </em>

The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent  

The more to the right, the metal is less reactive (harder to release electrons) and the stronger oxidizing agent

So that the metal located on the left can push the metal on the right in the redox reaction  

Let's analyze the statement in the problem

I. Only A, C and D react with 1 mol/L HCl to give H₂(e)

M + HCl ⇒ MCl + H₂(MCl : alkali, MCl₂ : alkaline earth)

A, C and D can react with 1 mol / L HCl, meaning metals A, C and D are located to the left of element H (more reactive), and B in the right of element H

II. When A is added to solutions of the other metal ions, metallic B and C are  formed but not D.

This means that metal A is more reactive than metals B and C, while D is more reactive than A, so metal D is the most reactive

3 0
3 years ago
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