At the bottom of a large cylindrical tank filled with fresh water the gauge pressure is 11.6 psi. What is the height (in feet) o
1 answer:
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Answer:
The inductor contains loops
Explanation:
From the question we are told that
The capacitance of the capacitor is
The resonance frequency is
The diameter is
The of the air-core inductor is
The permeability of free space is
Generally the inductance of this air-core inductor is mathematically represented as
This inductance can also be mathematically represented as
Where is the angular speed mathematically given as
So
Now equating the both formulas for inductance
making N the subject of the formula
Substituting value
loops
Answer:
Explanation:
Energy E is conserved:
If v₀ = 22m/s, h₀=0m and h₁=25m:
Solving for v₁:
There is no real solution, because the stone never reaches 25m.
The figure shows the arrangement of system
The velocity of boat can be resolved in to two
Horizontal component = vcos θ = 2.50 cos 45 = 1.768 m/s
Vertical component = vsin θ = 2.50 sin 45 = 1.768 m/s
Due to horizontal component the boat arrive arrives upstream,
Total horizontal velocity = 1.768 - Vr, where Vr is the velocity of river.
Total time taken to cross the river = width of river/ Vertical component of velocity
t = 285/1.768 = 161.20 seconds
So 118 meter is traveled at a velocity of 1.768-Vr in 161.20 seconds
That is 118 = (1.768-Vr)*161.20
1.768 - Vr =0.732
Vr = 1.036 m/s
So velocity of river flow =1.036 m/s
