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MariettaO [177]
3 years ago
12

Which of the following statements are true regarding the effect of flame temperature on atomic absorbance and atomic emission sp

ectroscopy?
I. Varying the flame temperature by 10 K hardly affects the ground-state population of the analyte and would not noticeably affect the analyte signal in atomic absorption.
II. Varying the flame temperature by 10 K hardly affects the excited-state population of the analyte and would not noticeably affect the analyte signal in atomic emission.
III. Varying the flame temperature by 10 K affects the ground-state population of the analyte and will noticeably affect the analyte signal in atomic absorption.
IV. Varying the flame temperature by 10 K affects the excited-state population of the analyte and will noticeably affect the analyte signal in atomic emission.
Select one:

a. I and II
b. III and IV
c. I and IV
d. II and IV
e. II and III
Chemistry
1 answer:
creativ13 [48]3 years ago
7 0

Answer:

the correct option is option c, I and IV

Explanation:

Atomic emission spectroscopy is used to determine quantity of element in a sample.

Atomic emission spectroscopy based on occurring of atomic emission when a valence electron from higher energy orbital comes back to lower energy orbital.

Light intensity emitted by a flame, plasma, arc of particular wavelength are used to excite the valence electron.

The intensity of atomic emission lines are proportional to number of atoms present in the excited state.

Emission intensity is affected by temperature of the excitation source and the efficiency of atomization.

Increase in temperature does not affect the ground state population.

Therefore, statements I and IV are correct.

So, the correct option is c.

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  • The<u> temperature</u> of the surroundings
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  • The <u>number of ice cubes </u>added to the water in the glass

In order to keep into consideration the changing environmental temperatures (which is a variable in the experiment), the experiment had to be conducted daily to get <u><em>accurate results </em></u>keeping into consideration all the factors.

brainly.com/question/11256472

7 0
2 years ago
Calcium bicarbonate (Ca(HCO3)2) Ca:H:C:O = 1:2:2 ___ Lithium sulfide (Li:2s) Li:S = 2:__
Anastaziya [24]

Answer: The ratio of atoms in calcium bicarbonate ; Ca : H : C : O = 1:2:2:6.

The ratio of atoms in lithium sulfide; Li : S = 2 : 1

Explanation:

In calcium bicarbonate:Ca(HCO_3)_2

In a molecular formula of calcium carbonate there are:

Number of Calcium atoms = 1

Number of Hydrogen atom = 1 × 2 = 2

Number of Carbon atoms = 1 × 2 = 2

Number of Oxygen atoms = 3 × 2 = 6

So, Ca : H : C : O = 1 : 2 : 2 : 6

In lithium sulfide :Li_2S

In a molecular formula of lithium sulfide there are:

Number of Lithium atoms =  1 × 2 = 2

Number of Sulfur atoms = 1

So, the Li : S = 2 : 1

8 0
3 years ago
Jupiters atmosphere is mostly made of ___
erastovalidia [21]
Jupiter's atmosphere is composed predominantly of hydrogen and helium, but if you have to select any one option then we can look at the percentage of existence of these elements that would be
<span>90 percent hydrogen.
remaining 10 percent is helium 
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3 0
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Zigmanuir [339]

Answer:

A and B

Explanation:

This is because there was emission of gamma (Y) radiations in both the reactions.

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Draw the products of the complete hydrolysis of an acetal. Draw all products of the reaction.
jolli1 [7]

Answer: the product is ketone or aldehyde

Explanation:

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H3O+/ ROH...

Attached is the structural conversion

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3 years ago
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