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MariettaO [177]
3 years ago
12

Which of the following statements are true regarding the effect of flame temperature on atomic absorbance and atomic emission sp

ectroscopy?
I. Varying the flame temperature by 10 K hardly affects the ground-state population of the analyte and would not noticeably affect the analyte signal in atomic absorption.
II. Varying the flame temperature by 10 K hardly affects the excited-state population of the analyte and would not noticeably affect the analyte signal in atomic emission.
III. Varying the flame temperature by 10 K affects the ground-state population of the analyte and will noticeably affect the analyte signal in atomic absorption.
IV. Varying the flame temperature by 10 K affects the excited-state population of the analyte and will noticeably affect the analyte signal in atomic emission.
Select one:

a. I and II
b. III and IV
c. I and IV
d. II and IV
e. II and III
Chemistry
1 answer:
creativ13 [48]3 years ago
7 0

Answer:

the correct option is option c, I and IV

Explanation:

Atomic emission spectroscopy is used to determine quantity of element in a sample.

Atomic emission spectroscopy based on occurring of atomic emission when a valence electron from higher energy orbital comes back to lower energy orbital.

Light intensity emitted by a flame, plasma, arc of particular wavelength are used to excite the valence electron.

The intensity of atomic emission lines are proportional to number of atoms present in the excited state.

Emission intensity is affected by temperature of the excitation source and the efficiency of atomization.

Increase in temperature does not affect the ground state population.

Therefore, statements I and IV are correct.

So, the correct option is c.

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A(g) + 2B(g) → C(g) + D(g)
WITCHER [35]

Answer:

0.169

Explanation:

Let's consider the following reaction.

A(g) + 2B(g) ⇄ C(g) + D(g)

We can find the pressures at equilibrium using an ICE chart.

       A(g) + 2 B(g) ⇄ C(g) + D(g)

I       1.00     1.00        0        0

C       -x        -2x        +x       +x

E    1.00-x  1.00-2x     x         x

The pressure at equilibrium of C is 0.211 atm, so x = 0.211.

The pressures at equilibrium are:

pA = 1.00-x = 1.00-0.211 = 0.789 atm

pB = 1.00-2x = 1.00-2(0.211) = 0.578 atm

pC = x = 0.211 atm

pD = x = 0.211 atm

The pressure equilibrium constant (Kp) is:

Kp = pC × pD / pA × pB²

Kp = 0.211 × 0.211 / 0.789 × 0.578²

Kp = 0.169

6 0
3 years ago
Are protons and neutrons electrically charged
blondinia [14]
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Answer:

They form a covalent bond

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Explanation:

solid: table, biscuit

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3 0
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A number should be rounded up if
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Answer:

C.) The number after it is between 5 and 9

Explanation:

If the digit to the right is less than five, you must leave the digit you want to round to as it is.

But, if the digit to the right is greater than or equal to five, you must increase the value of the digit you're rounding to by one. And any remaining digits before the decimal point become zeros, and any that are after the decimal point are dropped.

Hope this helps you out! : )

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