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3 years ago

Judy,Jeff and Jim each earned $5.40 raking leaves. How much did they earn together?

Mathematics

2 answers:

bearhunter [10]3 years ago

8 0

Answer:

$16.20

Step-by-step explanation:

Multiply 5.4 by 3 and that will give you the answer!

kvv77 [185]3 years ago

4 0

$16.20 dollars just do 5.4 times 3 and there is your answer

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The graph shows how much a plant grew after it was purchased. Which statement is not correct?

Luda [366]

Answer:

The plant grows 1 cm every day is the incorrect statement

Step-by-step explanation:

The graph shows that for every 10 days the plant grows 1 cm

10/2 = 5

so in 5 days the plant would grow half of what it does in 10 days so 1/2 or 0.5 cm

10/10 = 1

so in 1 day the plant would grow a tenth of what it does in 10 days so 1/10 or 0.1 cm

3 0

3 years ago

2-3*(z-5)+11=4 what is the value of z

wel

2-3(z-5)+11=4

Distribute

2-3z+15+11=4

Move the constants to gether but make sure they keep thei signs

2+15+11-3z=4

Simplify

28-3z=4

Start to Isolate the variable by subtracting 28 from both sides of the equation

-3z=-24

Completely isolate the variable by deviding the whole equation by -3

z=8

If you would like anything explained, just ask

6 0

3 years ago

Jesse bought a $340$ -gram bag of coffee beans. He uses $18.75$ grams of coffee beans each day. When there are $40$ grams of cof

IceJOKER [234]

Answer:

I will make sure he doesnt run out for you.

Step-by-step explanation:

3 0

3 years ago

3^x-3^(x-2)=A*3^x solve for A

ale4655 [162]

Answer:

$a=\frac{8}{9}$

Step-by-step explanation:

$3^x-3x^{x-2} =a3^x$

Divide both sides by $3^x$ :

$3^{x-x}-3^{x-x-2}=a$

Simplify:

$3^0-3^{-2}=a\\a=1-\frac{1}{9} \\a=\frac{8}{9}$

3 0

3 years ago

For the parallelogram ABCD the extensions of the angle bisectors AG and BH intersect at point P. Find the area of the parallelog

natita [175]

Answer:

The area of a parallelogram is 360 in.²

Step-by-step explanation:

Where DG = GH

GP = 12 in.

AB = 39 in.

∠DAB + ∠ABC = 180° (Adjacent angles of a parallelogram)

Whereby ∠DAB is bisected by AG and ∠ABC is bisected by BH

Therefore, ∠GAB + ∠HBA = 90°

Hence, ∠BPA = 90° (Sum of interior angles of a triangle)

$cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{AP}{39} = \dfrac{GP}{GH} =\dfrac{12}{GH}$

We note that ∠AGD = ∠GAB (Alternate angles of parallel lines)

∴ ∠AGD = ∠AGD since ∠AGD = ∠GAB (Bisected angle)

Hence AD = DG (Side length of isosceles triangle)

The bisector of ∠ADG is parallel to BH and will bisect AG at point Q

Hence ΔDAQ ≅ ΔDGQ ≅ ΔGPH and AQ = QG = GP

Hence, AP = 3 × GP = 3 × 12 = 36

$cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{36}{39}$

$\angle GAB = cos^{-1} \left (\dfrac{36}{39} \right )$

∠GAB = 22.62°

$cos(\angle GAB) = \dfrac{36}{39} = \dfrac{12}{GH}$

$GH = \dfrac{39}{36} \times {12}$

GH = 13 in.

∴ AD 13 in.

BP = 39 × sin(22.62°) = 15 in.

GH = √(GP² + HP²)

∠DAB = 2 × 22.62° = 45.24°

The height of the parallelogram = AD × sin(∠DAB) = 13 × sin(45.24°)

The height of the parallelogram = 120/13 = 9.23 in.

The area of a parallelogram = Base × Height = (120/13) × 39 = 360 in.²

7 0

3 years ago

Read 2 more answers