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yarga [219]
3 years ago
9

What is the energy stored, in units of nanoJoules, on a 14.8 nF capacitor when the voltage applied across the capacitor is 7.2 V

?

Physics
2 answers:
NeX [460]3 years ago
8 0
<h2>Answer:</h2>

<u>The energy stored will be  </u><u>3.83616e-7 J</u>

<h2>Explanation:</h2>

Since the energy stored is given by

E = 1/2 CV²

So putting the values

E = 1/2 * 1.48e-8 * (7.2)²

E = 3.83616e-7 Joules

AVprozaik [17]3 years ago
5 0

Answer:

383.6 nJ

Explanation:

The energy stored in a capacitor is given by the formula:

E=\frac{1}{2}CV^2

where

C is the capacitance

V is the voltage applied

In this problem, we have

C = 14.8 nF is the capacitance of the capacitor

V = 7.2 V is the voltage

Substituting into the equation, we find:

E=\frac{1}{2}(14.8 nF)(7.2 V)^2=383.6 nJ

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(a) If a long rope is hung from a ceiling and waves are sent. up the rope from its lower end, why does the speed of the waves ch
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My response to question (a) and (b) is that all of the element of the rope need to  aid or support the weight of the rope and as such, the tension will tend to increase along with height.

Note that It increases linearly, if the rope is one that do not stretch. So, the wave speed v= √ T/μ   increases with height.

<h3>How does tension affect the speed of a wave in a rope?</h3>

The Increase of the tension placed on a string is one that tends to increases the speed of a wave, which in turn also increases the frequency of any given length.

Therefore,  My response to question (a) and (b) is that all of the element of the rope need to  aid or support the weight of the rope and as such, the tension will tend to increase along with height.  Note that It increases linearly, if the rope is one that do not stretch. So, the wave speed v= √ T/μ   increases with height.

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(a) If a long rope is hung from a ceiling and waves are sent up the rope from its lower end, why does the speed of the waves change as they ascend? (b) Does the speed of the ascending waves increase or decrease? Explain.

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The minimum initial velocity that the ball must have for it to reach the top of the hill is 21 m/s. The correct option is D.

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The mechanical energy is the sum of kinetic energy and the potential energy of an object at any instant of time.

M.E = KE +PE

A boy is trying to roll a bowling ball up a hill. The friction is ignored.  The ball must have to reach the top of the hill with a velocity. The acceleration due to gravity, g = 9.8 m/s²

The conservation of energy principle states that total mechanical energy remains conserved in all situations where there is no external force acting on the system.

M.E bottom of hill = M.E on top of hill

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Thus, the minimum initial velocity that the ball must have for it to reach the top of the hill is 21 m/s.

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