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3 years ago

Fonts, colors, and cell styles are organized in _____ categories.

1 answer:

4 0

<span>Fonts, colors, and cell styles are organized in _____ categories.
The answer is theme and non theme categories</span>

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The set of points P(0, 3), Q(2, 0), R(4, -3) are collinear and the line has a slope of _____.

jok3333 [9.3K]

Answer:

-3/2,collinear.

Step-by-step explanation:

slope of PQ=(0-3)/(2-0)=-3/2

eq. of line PQ is

y-3=-3/2(x-0)

y-3=-3/2 x

or2y-6=-3x

or 3x+2y=6

if R(4,-3) lies on it,then

3(4)+2(-3)=6

12-6=6

or 6=6

which is true.

Hence points P,Q,R are collinear.

and line has aslope=-3/2

7 0

2 years ago

What is 6x(-496)=19x12

vichka [17]

Answer:

-19/248

Step-by-step explanation:

4 0

3 years ago

The height of adult males on a given South Pacific Island is approximately normally distributed with mean 65 inches and standard

zvonat [6]

Answer:

a) 0.59871

b) 0.22663

e) 0.95994

Step-by-step explanation:

The height of adult males on a given South Pacific Island is approximately normally distributed with mean 65 inches and standard deviation of 4 inches.

We solve using z score

z = (x-μ)/σ, where

x is the raw score

μ is the population mean = 65 inches

σ is the population standard deviation = 4 inches

a). Taller than 64 inches

This means x > 64

Hence,

64 - 65/4

=- 1/4 = -0.25

P-value from Z-Table:

P(x<64) = 0.40129

P(x>64) = 1 - P(x<64) = 0.59871

b.) shorter than 62 inches

Hence,

62 - 65/4

=- 3/4 =- 0.75

P-value from Z-Table:

P(x<62) = 0.22663

c.) between 64 inches and 68 inches

Hence,

for 64 inches

64 - 65/4

=- 1/4 = -0.25

P-value from Z-Table:

P(x = 64) = 0.40129

For 68 inches

Hence,

68 - 65/4

= 3/4= 0.75

P-value from Z-Table:

P(x = 68) = 0.77337

d.) between 58 and 68 inches

e.) taller than 58 inches

Hence,

58 - 65/4

= -6/4 = -1.5

P-value from Z-Table:

P(x<58) = 0.040059

P(x>58) = 1 - P(x<58) = 0.95994

7 0

3 years ago

A cube and a square pyramid were joined to form the composite solid. A cube with side lengths of 12 inches. A square pyramid wit

Zepler [3.9K]

Answer:

total surface area = 936 in²

Step-by-step explanation:

total surface area = surface area of the pyramid + surface area of the cube

1. surface area of the pyramid = 4 * area of lateral triangle side

area of lateral triangle side = 12 * 9 /

area of lateral triangle side = 54 in²

2. surface area of the pyramid = 4 * 54

surface area of the pyramid = 216 in²

3. surface area of the cube = 5 * (12 x 12)

-surface area of the cube = 720 in²

therefore, the total surface area = 216 in² + 720 in²

total surface area = 936 in²

8 0

3 years ago

Read 2 more answers

Jamie is riding a Ferris wheel that takes fifteen seconds for each complete revolution. The diameter of the wheel is 10 meters a

Agata [3.3K]

Answer:

The answers to the question is

(a) Jamie is gaining altitude at 1.676 m/s

(b) Jamie rising most rapidly at t = 15 s

At a rate of 2.094 m/s.

Step-by-step explanation:

(a) The time to make one complete revolution = period T = 15 seconds

Here will be required to develop the periodic motion equation thus

One complete revolution = 2π,

therefore the we have T = 2π/k = 15

Therefore k = 2π/15

The diameter = radius of the wheel = (diameter of wheel)/2 = 5

also we note that the center of the wheel is 6 m above ground

We write our equation in the form

y = $5*sin(\frac{2*\pi*t}{15} )+6$

When Jamie is 9 meters above the ground and rising we have

9 = $5*sin(\frac{2*\pi*t}{15} )+6$ or 3/5 = $sin(\frac{2*\pi*t}{15} )$ = 0.6

which gives sin⁻¹(0.6) = 0.643 = $\frac{2*\pi*t}{15}$

from where t = 1.536 s

Therefore Jamie is gaining altitude at

$\frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi t}{15}) =$ 1.676 m/s.

(b) Jamie is rising most rapidly when the velocity curve is at the highest point, that is where the slope is zero

Therefore we differentiate the equation for the velocity again to get

$\frac{d^2y}{dx^2} = -5*(\frac{\pi *2}{15} )^2*sin(\frac{2\pi t}{15})$ =0, π, 2π

Therefore $-sin(\frac{2\pi t}{15} )$ = 0 whereby t = 0 or

$\frac{2\pi t}{15}$ = π and t = 7.5 s, at 2·π t = 15 s

Plugging the value of t into the velocity equation we have

$\frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi t}{15}) =$ - 2/3π m/s which is decreasing

so we try at t = 15 s and we have $\frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi *15}{15}) = \frac{2}{3} \pi$ m/s

Hence Jamie is rising most rapidly at t = 15 s

The maximum rate of Jamie's rise is 2/3π m/s or 2.094 m/s.

7 0

3 years ago