Answer:
The frictional force acting on the bear during the slide is 207.5 N
Explanation:
Given;
mass of beam, m = 25-kg
vertical height, h = 12 m
speed of fall, v = 6 m/s
Change in potential energy of the beam:
ΔP.E = -mgh = - 25 x 9.8 x 12 = -2940 J
Change in kinetic energy of the beam:
Δ K.E = ¹/₂mv² = ¹/₂ x 25 x (6)² = 450 J
Change in thermal energy of the system due to friction:
ΔE = - (ΔP.E + Δ K.E)
ΔE = - (-2940 J + 450 J)
ΔE = 2940 J - 450 J = 2490 J
Frictional force (in N) acting on the bear during the slide:
F x d = Fk x h = ΔE
Where;
Fk is the frictional force
Fk = ΔE/h
Fk = 2490J / 12m
Fk = 207.5 N
Therefore, the frictional force acting on the bear during the slide is 207.5 N
No if in the light it would be always half lit
Answer:
Given:
Mass (M) = 7917 grams
Volume (V)= 754 cm³
To Find:
Density of the substance
Explanation:
Substituting values of M & V in the equation:
Answer:
CONDUCTION
Energy transfers from one
object to another by direct
contact
CONVECTION
Energy transfers via the
movement of particles
within a liquid or gas.
RADIATION
Energy transfers by
electromagnetic waves as
they travel through space or
matter
Explanation:
As we know that with respect to oxygen atom taken as reference the product of atomic mass and specific heat of a metal will remain constant.
this product is equal to 0.38
so here we will say that let atomic mass of the metal is M
so with respect to oxygen atom its mass is given as
now we will have
now we will have
so atomic mass of the metal is 7 g/mol
