Answer:
The answer to your question is: 1.21 x 10 ²⁴ particles of N₂O
Explanation:
Data
# of particles = 2.02 moles of N₂O
1 mol of N₂O ---------------- 6.023 x 10 ²³ particles
2.02 moles ---------------- x
x = (2.02 x 6.023 x 10²³) / 1
x = 1.21 x 10 ²⁴ particles of N₂O
The formula for pH given the pKa and the concentrations
are:
pH = pKa + log [a–]/[ha]
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Therefore calculating:</span>
3.75 = 3.75 + log [a–]/[ha]
log [a–]/[ha] = 0
[a–]/[ha] = 10^0
<span>[a–]/[ha] = 1</span>
Answer:
Ba(OH)₂ requires more H₂SO₄ to reach neutralization..
Explanation:
- At neutralization, acid neutralize base to form salt and water at equivalence.
- NH₄OH is neutralized by H₂SO₄ according to the reaction:
<em>2NH₄OH + H₂SO₄ → (NH₄)₂SO₄ + 2H₂O.</em>
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It is clear that every 2 mol of NH₄OH need 1 mol of H₂SO₄ to be neutralized.
- Ba(OH)₂ is neutralized by H₂SO₄ according to the reaction:
<em>Ba(OH)₂ + H₂SO₄ → BaSO₄ + 2H₂O.</em>
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It is clear that every 1 mol of NH₄OH needs 1 mol of H₂SO₄ to be neutralized.
<em>So, Ba(OH)₂ requires more H₂SO₄ to reach neutralization.</em>
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