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MrRissso [65]
3 years ago
7

When nitrogen and magnesium form an ionic bond, what is the formula?

Chemistry
2 answers:
prisoha [69]3 years ago
8 0
Mg ^+2 N^-3

Mg3N2. Magnesium nitride. I believe this would be the chemical formula.
BaLLatris [955]3 years ago
5 0

<u>Answer:</u> The chemical formula for the given compound is Mg_3N_2

<u>Explanation:</u>

Magnesium is the 12th element of the periodic table having electronic configuration of [Ne]3s^2

This element will loose 2 electrons and form an oxidation state of +2 units.

Nitrogen is the 7th element of the periodic table having electronic configuration of [He]2s^22p^3

This element requires 3 electrons and thus shows an oxidation state of -3 units.

By criss-cross method, the oxidation state of the ions gets exchanged and this form the subscripts of the other ions. It results in the formation of a neutral compound.

Thus, the chemical formula for the given compound is Mg_3N_2

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If 34.7 g of AgNO₃ react with 28.6 g of H₂SO₄ according to this UNBALANCED equation below, how many grams of Ag₂SO₄ could be for
Luba_88 [7]

The  number  of grams   of Ag2SO4  that could be formed  is   31.8  grams



    <u><em> calculation</em></u>

Balanced   equation is  as below

2 AgNO3 (aq)  + H2SO4(aq)  →  Ag2SO4 (s)   +2 HNO3 (aq)


  • Find  the  moles  of  each reactant by use  of  mole= mass/molar mass  formula

that is  moles of  AgNO3= 34.7 g / 169.87  g/mol= 0.204 moles

             moles of  H2SO4 =  28.6  g/98  g/mol  =0.292  moles

  • use the  mole  ratio to determine the moles of  Ag2SO4

   that is;

  •    the mole ratio of  AgNo3 : Ag2SO4 is  2:1 therefore  the  moles of Ag2SO4=  0.204  x1/2=0.102 moles

  • The moles  ratio of H2SO4  : Ag2SO4  is  1:1  therefore  the moles of Ag2SO4 = 0.292  moles

 

  •      AgNO3  is the limiting reagent therefore  the moles of   Ag2SO4 = 0.102  moles

<h3>     finally  find  the mass  of Ag2SO4  by use of    mass=mole  x molar mass  formula</h3>

that  is  0.102   moles  x  311.8  g/mol= 31.8 grams

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<em>Hence, in this case, if the concentration of the products of a reaction in equilibrium is increased, the equilibrium would shift in such a way that more reactants are formed so as to annul the effects created by the increase in the concentration of the products. Since reactants are always on the left side of chemical equations, it thus means that the equilibrium would shift to the left.</em>

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