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3 years ago

When nitrogen and magnesium form an ionic bond, what is the formula?

Chemistry

2 answers:

prisoha [69]3 years ago

8 0

Mg ^+2 N^-3

Mg3N2. Magnesium nitride. I believe this would be the chemical formula.

BaLLatris [955]3 years ago

5 0

Answer: The chemical formula for the given compound is $Mg_3N_2$

Explanation:

Magnesium is the 12th element of the periodic table having electronic configuration of $[Ne]3s^2$

This element will loose 2 electrons and form an oxidation state of +2 units.

Nitrogen is the 7th element of the periodic table having electronic configuration of $[He]2s^22p^3$

This element requires 3 electrons and thus shows an oxidation state of -3 units.

By criss-cross method, the oxidation state of the ions gets exchanged and this form the subscripts of the other ions. It results in the formation of a neutral compound.

Thus, the chemical formula for the given compound is $Mg_3N_2$

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Too much can lead to diabetes and can be stored as fat in the body

ohaa [14]

Answer:B.carbohydrates

Explanation:

7 0

2 years ago

A beaker with 155 mL of an acetic acid buffer with a pH of 5.000 is sitting on a benchtop. The total molarity of acid and conjug

OverLord2011 [107]

Answer:

ΔpH = 0.296

Explanation:

The equilibrium of acetic acid (CH₃COOH) in water is:

CH₃COOH ⇄ CH₃COO⁻ + H⁺

Henderson-Hasselbalch formula to find pH in a buffer is:

pH = pKa + log₁₀ [CH₃COO⁻] / [CH₃COOH]

Replacing with known values:

5.000 = 4.740 + log₁₀ [CH₃COO⁻] / [CH₃COOH]

0.260 = log₁₀ [CH₃COO⁻] / [CH₃COOH]

1.820 = [CH₃COO⁻] / [CH₃COOH] (1)

As total molarity of buffer is 0.100M:

[CH₃COO⁻] + [CH₃COOH] = 0.100M (2)

Replacing (2) in (1):

1.820 = 0.100M - [CH₃COOH] / [CH₃COOH]

1.820[CH₃COOH] = 0.100M - [CH₃COOH]

2.820[CH₃COOH] = 0.100M

[CH₃COOH] = 0.100M / 2.820

[CH₃COOH] = 0.035M

Thus: [CH₃COO⁻] = 0.100M - 0.035M = 0.065M

5.40 mL of a 0.490 M HCl are:

0.0054L × (0.490mol / L) = 2.646x10⁻³ moles HCl.

Moles of CH₃COO⁻ are: 0.155L × (0.065mol / L) = 0.0101 moles

HCl reacts with CH₃COO⁻ thus:

HCl + CH₃COO⁻ → CH₃COOH

After reaction, moles of CH₃COO⁻ are:

0.0101 moles - 2.646x10⁻³ moles = 7.429x10⁻³ moles of CH₃COO⁻

Moles of CH₃COOH before reaction are: 0.155L × (0.035mol / L) = 5.425x10⁻³ moles of CH₃COOH. As reaction produce 2.646x10⁻³ moles of CH₃COOH, final moles are:

5.425x10⁻³ moles + 2.646x10⁻³ moles = 8.071x10⁻³ moles of CH₃COOH. Replacing these values in Henderson-Hasselbalch formula:

pH = 4.740 + log₁₀ [7.429x10⁻³ moles] / [8.071x10⁻³ moles]

pH = 4.704

As initial pH was 5.000, change in pH is:

ΔpH = 5.000 - 4.740 = 0.296

4 0

3 years ago

How many coppers of each atom in the products

yarga [219]

Answer:

Explanation:

moler mass of Cu is 63.546 g/mol. Since 63.546 g of copper has 6.022 x 10 power(23) atoms (Avogadro's number). = 9.5 x 10(power)21 atoms of copper.

6 0

2 years ago

One atom of an element possesses 80 protons, 80 electrons, and 121 neutrons. Given this information, what is the atomic mass of

IRINA_888 [86]

Answer:

I think the answer is 4) 41

Explanation:

APE= atomic number, proton and the electrons are the same number

MAN= mass = atomic number - neutrons

121 - 80 = 41

i haven't done this in a while so hope this helps :)

3 0

2 years ago

Which solution contains the smallest number of moles of sucrose (c12h22o11, molar mass = 342.30 g/mol)? 2,000 ml of a 5.0 × 10–5

Iteru [2.4K]

> 2,000 mL of a 5.0 × 10–5% (w/v) sucrose solution

5.0 × 10–3 g/mL * 2000 mL * (1 mol / 342.30 g) = 0.0292 mol

> 2,000 mL of a 5.0 ppm sucrose solution

5 grams / 1000000 mL * 2000 mL* (1 mol / 342.30 g) = 0.0000292 mol

> 20 mL of a 5.0 M sucrose solution

5.0 M * 0.020 L = 0.1 mol

Answer:

2,000 mL of a 5.0 ppm sucrose solution

5 0

3 years ago