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3 years ago

Which horizon has the least weathered rocks? How do you know?

Chemistry

1 answer:

ollegr [7]3 years ago

4 0

Answer:

C: The C horizon is a subsurface horizon. It is the least weathered horizon. Also known as the saprolite, it is unconsolidated, loose parent material. The master horizons may be followed by a subscript to make further distinctions between differences within one master horizon.

Explanation:

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A newspaper story describing the local celebration of Mole Day on October 23 (selected for Avogadro's number, 6.02 X 10^ 23 ) at

stepladder [879]

Answer:

The answer is "670.176 km".

Explanation:

Volume of the occupies of one M & M= 0.5 \ cm^3\\\\

M&M 1 mole $= 6.02 \times 10^{23}\\\\$

Calculating volume of M& M mole $= 0.5 \ cm^3 \times 6.02 \times 10^{23}=3.01 \times 10^{23}\ cm^3\\\\$

Calculating the cube mole $L^3= 3.01 \times 10^{23}\ cm^3\\\\$

$L=6.70176 \times 10^{7}\ cm\\\\$

$=6.70176 \times 10^{7}\ cm \times \frac{1\ m}{100\ cm}\\\\=670176\ m\\\\=670.176 \ km$

Therefore 18 tractor trailers wouldn't be sufficient.

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3 years ago

Think about how particles are arranged inside atoms. Please name and describe those three particles, and describe how the partic

vekshin1

Protons : positive charge , about same mass as neutrons , in the nucleus

neutrons : no charge , about the same mass as a proton , in the nucleus

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3 years ago

A student placed 15.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then

Ede4ka [16]

Answer: The mass of glucose in final solution is 1.085 grams

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$ ......(1)

Given mass of glucose = 15.5 g

Molar mass of glucose = 180.2 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$\text{Molarity of glucose solution}=\frac{15.5\times 1000}{180.2\times 100}\\\\\text{Molarity of glucose solution}=0.860M$

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated glucose solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted glucose solution

We are given:

$M_1=0.860M\\V_1=35.0mL\\M_2=?M\\V_2=0.500L=500mL$

Putting values in above equation, we get:

$0.860\times 35.0=M_2\times 500\\\\M_2=\frac{0.860\times 35.0}{500}=0.0602M$

Now, calculating the mass of glucose by using equation 1, we get:

Molarity of glucose solution = 0.0602 M

Molar mass of glucose = 180.2 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$0.0602=\frac{\text{Mass of glucose solution}\times 1000}{180.2\times 100}\\\\\text{Mass of glucose solution}=\frac{0.0602\times 180.2\times 100}{1000}=1.085g$

Hence, the mass of glucose in final solution is 1.085 grams

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3 years ago

Sentences with biocycle

dusya [7]

Associating the need of surgeon in practice , we write a software of human body biocycle law . this software can provide a science reliance in the time selection of surgical operation plan to the main surgeon
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4 years ago

Oliver needs to standardize a base solution by titration with an acid solution of known concentration. He finds the volume of th

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Write a balance equation for the reaction between the analyte and the titrant.
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Calculate the # of moles of analyte using the stoichiometric coefficients of the equation.
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3 years ago