Answer:
<em><u>B</u></em><em><u> </u></em><em><u>.</u></em><em><u>8</u></em><em><u>0</u></em><em><u>5</u></em><em><u> </u></em><em><u>mL</u></em>
Explanation:
Here, temperature is constant!
so we can use P1V1=P2V2
P1,V1 is pressure and volume in original condition
and P2V2, pressure and volume in new condition!
now, volume is given 900mL(=V1)
standard pressure is 1 atm i.e, 760mmHg(=P1)
pressure increases to 850mmHg(=P2)
now we have,
P1V1=P2V2
i.e, 760mmHg×900mL=850mmHg×V2
i.e, V2={(900×760)/850 } mL
=804.75 mL
≈805mL
✌️:)