Answer:
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In order to apply the principle of conservation of mass to this reaction, we must prove that the mass on the left hand side is equivalent to the mass on the right hand side. In order to do this, we must first acquire the atomic masses of each substance involved. These are:
Fe - 56
O - 16
Now, we substitute these values into the equation:
4(56) + 3(2*16) = 2(56 * 2 + 16 * 3)
224 + 96 = 320
320 = 320
As we can see, the principle of conservation of mass holds true.
Answer:
56.24g
Explanation:
To find the mass of N2O3 in 4.45 x 10^23 molecules, it must first be converted to moles by dividing the number of molecules in N2O3 by Avagadro's number (6.02 × 10^23).
number of moles in N2O3 = 4.45 x 10^23 ÷ 6.02 × 10^23
n = 4.45/6.02 × 10^(23 - 23)
n = 0.74 × 10^0
n = 0.74moles.
Using the formula below to find the mass of N2O3;
mole = mass ÷ molar mass
Molar mass of N2O3 = 14(2) + 16(3)
= 28 + 48
= 76g/mol
mass = mole × molar mass
Mass = 0.74 × 76
Mass = 56.24g
1 mol of any substance is made of 6.022 x 10²³ units.
When its 1 mol of a formula, its made of 6.022 x 10²³ formula units
Therefore if 6.022 x 10²³ formula units of CeI₃ make up 1 mol of CeI₃
Then 9.42 x 10²¹ formula units make up - 1/(6.022 x 10²³) x (9.42 x 10²¹) = 0.0156 mol of CeI₃
Therefore number of moles of CeI₃ - 0.0156 mol
The answer is to heat the water up to increase the rate that which it dissolves
