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just olya [345]
3 years ago
8

What happens when an electrically charged balloon is placed close to an uncharged soda can?

Physics
2 answers:
Gemiola [76]3 years ago
6 0

Answer:

The surface closest to the balloon becomes positively charged, while the far side of the can becomes negatively charged. This results in an attractive force that draws the can to the balloon.

Explanation:

Artyom0805 [142]3 years ago
5 0

Answer:

The balloon is negatively charged.

Explanation:

hope it helps

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You cross two pure tall (TT) plants with two pure short (tt) plants and produce four offspring. Which of the following statement
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what would the net force be on the box in the problems shown below.( both force and direction).​ for all four diagrams. please e
DIA [1.3K]

Answer:
A) object moves 20 N [West] or -20 N [East]
B) object moves 6 N [South] or -6 N [North]
C) object moves 90 N [West] or -90 N [East]
D) object does not move and is at rest*

*Rest means 0


Why:

A)both forces from north and south that are pushing against the object neutralize each other. Assume that north is positive and south is negative: 20 [N] + (-20) [S] = 0
On West and east, you can see that west has a greater force. Assume that west is negative and east is positive: 50 [E] + (-70) [W] = -20 [E]
8 0
3 years ago
A family has a furnace that uses natural gas to heat their home. They are moving to an area that offers the option of using ener
Murrr4er [49]

The disadvantage will the family most likely face by making this switch is that solar power has a less reliable production of heat.Option A is correct.

<h3>What is a power plant?</h3>

A power plant is an industrial structure that generates electricity. The majority of power plants are linked to the electrical grid.

Nuclear power bare a form of the thermal power plant. You have a reactor where fission takes place and heat is generated, a heat exchanger that transports this heat to where it is needed.

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Hence option A is correct,

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brainly.com/question/7670779

#SPJ1

8 0
2 years ago
A 45 kg bear slides, from rest, 11 m down a lodgepole pine tree, moving with a speed of 5.8 m/s just before hitting the ground.
Viefleur [7K]

Answer:

Explanation:

a )

change  in the gravitational potential energy of the bear-Earth system during the slide  = mgh

= 45 x 9.8 x 11

= 4851 J

b )

kinetic energy of bear just before hitting the ground

= 1/2 m v²

= .5 x 45 x 5.8²

= 756.9 J

c ) If  the average frictional force that acts on the sliding bear be F

negative work done by friction

= F x 11 J

then ,

4851 J -  F x 11 =  756.9 J

F x 11 = 4851 J -   756.9 J

= 4094.1 J

F = 4094.1 / 11

= 372.2 N  

4 0
3 years ago
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