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alekssr [168]
3 years ago
13

I give 10 points for 3 tasks + BRAINLIEST!!!!

Chemistry
1 answer:
Marta_Voda [28]3 years ago
6 0
<span>21. F, Cl and Br.

22. </span>Since it is in Group 3 it will have 3 valence electrons. When you draw the Lewis structure for Aluminum you'll put three<span> "dots" or valence electrons around the element symbol.

23. </span><span>you would need 2 group 17's for every 1 group 2</span>
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Practice Problem: True Stress and Strain A cylindrical specimen of a metal alloy 49.7 mm long and 9.72 mm in diameter is stresse
amm1812

Answer:

The true stress required = 379 MPa

Explanation:

True Stress is the ratio of the internal resistive force to the instantaneous cross-sectional area of the specimen. True Strain is the natural log to the extended length after which load applied to the original length. The cold working stress – strain curve relation is as follows,

σ(t) = K (ε(t))ⁿ, σ(t) is the true stress, ε(t) is the true strain, K is the strength coefficient and n is the strain hardening exponent

True strain is given  by

Epsilon t =㏑ (l/l₀)

Substitute㏑(l/l₀) for ε(t)

σ(t) = K(㏑(l/l₀))ⁿ

Given values l₀ = 49.7mm, l =51.7mm , n =0.2 , σ(t) =379Mpa

379 x 10⁶ = K (㏑(51.7/49.7))^0.2

K = 379 x 10⁶/(㏑(51.7/49.7))^0.2

K = 723.48 MPa

Knowing the constant value would be same as the same material is being used in the second test, we can find out the true stress using the above formula replacing the value of the constant.

σ(t) = K(㏑(l/l₀))ⁿ

l₀ = 49.7mm, l = 51.7mm, n = 0.2, K = 723.48Mpa

σ(t) = 723.48 x 106 x (㏑(51.7/49.7))^0.2

σ(t) = 379 MPa

The true stress necessary to plastically elongate the specimen is 379 MPa.

6 0
3 years ago
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What is the chemical formula of the following compound
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A. C3H10 is the answer
6 0
2 years ago
Tin metal reacts with hydrogen fluoride to produce tin (ll )fluoride and hydrogen gas according to the balanced equation. Sn(s)+
ladessa [460]

Answer:

                      1.263 moles of HF

Explanation:

                     The balance chemical equation for given single replacement reaction is;

                                    Sn + 2 HF → SnF₂ + H₂

Step 1: <u>Calculate Moles of Tin as;</u>

As we know,

                    Moles  =  Mass / A.Mass    ----- (1)

Where;

           Mass of Tin  =  75.0 g

           A.Mass of Tin  =  118.71 g/mol

Putting values in eq. 1;

                    Moles  =  75.0 g / 118.71 g/mol

                    Moles  =  0.6318 moles of Sn

Step 2: <u>Find out moles of Hydrogen Fluoride as;</u>

According to balance chemical equation,

                     1 mole of Sn reacted with  =  2 moles of HF

So,

              0.6318 moles of Sn will react with  =  X moles of HF

Solving for X,

                     X =  0.6318 mol × 2 mol / 1 mol

                     X  =  1.263 moles of HF

8 0
2 years ago
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