Answer:
Chemical energy.
Explanation:
This is biology btw, not chemistry
Answer:
Increase
Explanation:
If temperature is held constant, the equation is reduced to Boyle's law. Therefore, if you decrease the pressure of a fixed amount of gas, its volume will increase.
Answer:
Option A = it dies
Explanation:
Homeostasis:
It is the ability of organisms to maintain the equilibrium in its internal environment in order to deal with external environmental changes.
If the unicellular organism cannot maintain the homeostasis it would die.
Importance of homeostasis:
It is constant chemical and physical condition of cell. The unicellular organisms in maintained homeostasis condition can grow and reproduce. They respond to the environment and transfer energy. It is the primary objective of unicellular organism other wise they would not survive.
It is very important for them because they totally rely on it and can perform the necessary functions of life.
While in case of multi cellular organisms all cells communicate with each other to maintain the homeostasis.
Answer:
Pressure for H₂ = 11.9 atm
Option 5.
Explanation:
We determine the complete reaction:
2Al(s) + 6HCl(aq) → 2AlCl₃(aq) + 3H₂(g)
As we do not know anything about the HCl, we assume that the limiting reactant is the Al and the acid is the excess reagent.
Ratio is 2:3.
2 moles of Al, can produce 3 moles of hydrogen
Therefore 4.5 moles of Al must produce (4.5 . 3) / 2 = 6.75 moles
Now we can apply the Ideal Gases law to find the H₂'s pressure
P . V = n . R . T → P = (n . R .T) / V
We replace data: (6.75 mol . 0.082L.atm/mol.K . 300K) / 14L
Pressure for H₂ = 11.9 atm
Answer:
596K
Explanation:
Using Charles law equation;
V1/T1 = V2/T2
Where;
V1 = initial volume (L)
V2 = final volume (L)
T1 = initial temperature (K)
T2 = final temperature (K)
According to the information provided in this question,
V1 = 3.00 L
V2 = double of V1 = 2 × 3.00 = 6.00 L
T1 = 25°C = 25 + 273 = 298K
T2 = ?
Using V1/T1 = V2/T2
3/298 = 6/T2
Cross multiply
298 × 6 = 3 × T2
1788 = 3T2
T2 = 1788 ÷ 3
T2 = 596K