Answer:
E = k*Q₁/R₁² V/m
V = k*Q₁/R₁ Volt
Explanation:
Given:
- Charge distributed on the sphere is Q₁
- The radius of sphere is R₁
- The electric potential at infinity is 0
Find:
What is the electric field at the surface of the sphere?E.
What is the electric potential at the surface of the sphere?V
Solution:
- The 3 dimensional space around a charge(source) in which its effects is felt is known in the electric field.
- The strength at any point inside the electric field is defined by the force experienced by a unit positive charge placed at that point.
- If a unit positive charge is placed at the surface it experiences a force according to the Coulomb law is given by
F = k*Q₁/R₁²
- Then the electric field at that point is
E = F/1
E = k*Q₁/R₁² V/m
- The electric potential at a point is defined as the amount of work done in moving a unit positive charge from infinity to that point against electric forces.
- Thus, the electric potential at the surface of the sphere of radius R₁ and charge distribution Q₁ is given by the relation
V = k*Q₁/R₁ Volt
She misses. She should have accelerated faster in order to get to her target.
5.8 moles of nitrogen gas are needed to pressurize the air bag.
<h3>What's the expression of Ideal gas equation?</h3>
- Ideal gas equation is PV=nRT
- P= pressure, V = volume, n= no. of moles of gas, R= universal gas constant, T = temperature of the gas
<h3>What's the no. of moles of nitrogen present in a 60L air bag at 2.37 atm pressure and 25°C temperature?</h3>
- P= 2.37 atm, V = 60L, R= 0.0821 L-atm/mol-K, T = 25°C = 298K
- n= PV/RT
= (2.37×60)/(0.0821×298)
= 5.8 moles
Thus, we can conclude that 5.8 moles of nitrogen gas are needed to pressurize the air bag.
Learn more about the ideal gas here:
brainly.com/question/20348074
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Well you never specified what you're asking... however, this might help you learn the concepts of displacements and magnitude.
: The official displacement formula is as follows: s = sf - si. s = displacement; si = initial position; sf = final position
magnitude is the quantitative value of seismic energy. It is a specific value having no relation with distance and direction of the epicentre.
the magnitude of a vector in any dimension. For a 2d vector the formula is [math]|z| = \sqrt{x^2+y^2}[/math], where x and y are the x and y components of the vector respectively.
