00 mL? I believe that you have erroneously pasted the
question here.
Anyway, let us continue computing for the molarity of KOH
but i will just use a variable “A” for the volume of H2SO4 solution.
The complete balanced reaction is:
H2SO4 + 2KOH
--> K2SO4 + 2H2O
We see that 2 moles of KOH is needed for every mole of
H2SO4. So calculate the moles of H2SO4.
moles H2SO4 = 0.245 M * (A / 1000) = 2.45x10^-4 A
So the number of moles of KOH is:
moles KOH = 2.45x10^-4 A * 2
moles KOH = 4.90x10^-4 A
So the molarity of KOH is:
Molarity KOH = 4.90x10^-4 A / (0.0239 L)
Molarity KOH = 0.0205 * A
Simply multiply 0.0205 by the correct volume of H2SO4 in
ml
B, If a force pushes the rock, it rolls down the hill because of the force of gravity. The potential energy is converted into kinetic energy until it reaches the bottom of the hill and stops. The water in a reservoir behind a hydropower dam is another example of potential energy.
The conclusion includes a summary of the results, whether or not the hypothesis was supported, the significance of the study, and future research.
Answer:
Higher oxidation state metals form stronger bong with ligands
Explanation:
Ligand strength are based on oxidation number, group and its properties
Do DIMENSIONAL Analysis what comes up must come down