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3 years ago

What will be the charge of an atom containing eight protons, nine neutrons, and 10 electrons?

Chemistry

1 answer:

Wittaler [7]3 years ago

6 0

The charge would be -2 because there are 2 more electrons than protons, and electrons have a negative charge.

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You have a balloon containing 1 L of air at STP in a vacuum chamber. What will the volume of the balloon be when you reduce the

Ipatiy [6.2K]

P1V1/T1=P2V2/T2 P2=1/2 P1 V1=1 T1=298K

1 P1/298= (1/2) P1V2/373 cross P1

1/298=1/2V2/373
1/298=1/V2 746
v2=746/298
V2=2.5L

5 0

3 years ago

Hello can you please help me to solve above fill in the blank questions

LiRa [457]

Answer:

C2H5OH is a formula of ethyl alchol or ethanol.

alkenes are characterisized by carbon-carbon double bond.

burning is an example of exothermic reaction

atomic number of element is x the symbol of its ion is +1 bcz it will lose one electron

if temperature increases then rate of chemical reaction increases

Explanation:

i hope this will help you :)

7 0

3 years ago

A 10.21 mol sample of argon gas is maintained in a 0.7564 L container at 296.9 K. What is the pressure in atm calculated using t

soldi70 [24.7K]

Answer:

The pressure in atm calculated using the van der Waals' equation, is 337.2atm

Explanation:

This is the Van der Waals equation for real gases:

(P + a/v² ) ( v-b) = R .T

where P is pressure

v is Volume/mol

R is the gas constant and T, T° in K

a y b are constant for each gas, so those values are data, from the statement.

[P + 1.345 L²atm/mol² / (0.7564L/10.21mol)² ] (0.7564L/10.21mol - 3.219×10-2 L/mol ) = 0.082 L.atm/mol.K . 296.9K

[P + 1.345 L²atm/mol² / 5.48X10⁻³ L²/mol²] (0.074 L/mol - 3.219×10-2 L/mol ) = 0.082 L.atm/mol.K . 296.9K

(P + 245.05 atm) (0.04181L/mol) = 0.082 L.atm/mol.K . 296.9K

(P + 245.05 atm) (0.04181L/mol) = 24.34 L.atm/mol

0.04181L/mol .P + 10.24 L.atm/mol = 24.34 L.atm/mol

0.04181L/mol .P = 24.34 L.atm/mol - 10.24 L.atm/mol

0.04181L/mol. P = 14.1 L.atm/mol

P = 14.1 L.atm/mol / 0.04181 mol/L

P = 337.2 atm

4 0

2 years ago

Use enthalpies of formation given in appendix c to calculate δh for the reaction br2(g)→2br(g), and use this value to estimate t

Contact [7]

Given reaction represents dissociation of bromine gas to form bromine atoms

Br2(g) ↔ 2Br(g)

The enthalpy of the above reaction is given as:

ΔH = ∑n(products)Δ $H^{0}f(products)$ - ∑n(reactants)Δ $H^{0}f(reactants)$

where n = number of moles

Δ $H^{0}f$ = enthalpy of formation

ΔH = [2*ΔH(Br(g)) - ΔH(Br2(g))] = 2*111.9 - 30.9 = 192.9 kJ/mol

Thus, enthalpy of dissociation is the bond energy of Br-Br = 192.9 kJ/mol

3 0

3 years ago

70<br><br> What is 27/100 plus 3/10 equals

Brut [27]

Answer:

that is my answer hope it helps you out

Explanation:

i got 1.40 for my answer

6 0

2 years ago