The inner diameter for a steel stack that exhausts 1,200 m3/min of gases at 1 atm and 400 k is 1.45 m
<h3>What is Stack Height ?</h3>
Stack height means the distance from the ground-level elevation at the base of the stack to the crown of the stack.
If a stack arises from a building or other structure, the ground-level elevation of that building or structure will be used as the base elevation of the stack.
Given is a steel stack that exhausts 1,200 cu.m/min of gases
P= 1 atm and
T= 400 K
maximum expected wind speed at stack height of 12 m/s
The formula for the diameter of chimney
Q =1200 cu.m/min
= 1200 * 0.0166 = 19.92 cu.m/sec
Velocity = 12m/s
d= 1.45 m
Therefore The inner diameter for a steel stack that exhausts 1,200 m3/min of gases at 1 atm and 400 k is 1.45 m.
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Answer:
A Chemical equation is balanced if the reactants side of the chemical reaction has the same number total of atoms of elements as the products side of the chemical equation. While a Chemical equation is unbalanced if the reactants side of the chemical reaction has a different number total of atoms of elements as the products side of the chemical equation
Explanation:
Self explanatory
Answer:
chocolate
Explanation:
chocolate is 17,196 litres per 1kg.
Answer:
c = 0.377 J/g.°C
c = 0.2350 J/g.°C
J = 27.3 J
Explanation:
We can calculate the heat (Q) absorbed or released by a substance using the following expression.
Q = c × m × ΔT
where,
c: specific heat
m: mass
ΔT: change in the temperature
<em>It takes 49.0J to raise the temperature of an 11.5g piece of unknown metal from 13.0°C to 24.3°C. What is the specific heat for the metal? Express your answer numerically, in J/g.°C</em>
Q = c × m × ΔT
49.0 J = c × 11.5 g × (24.3°C - 13.0°C)
c = 0.377 J/g.°C
<em>The molar heat capacity of silver is 25.35 J/mol.°C. How much energy would it take to raise the temperature of 11.5g of silver by 10.1°C? Express your answer numerically, in Joules. What is the specific heat of silver?</em>
<em />
The molar mass of silver is 107.87 g/mol. The specific heat of silver is:
Q = c × m × ΔT
Q = (0.2350 J/g.°C) × 11.5 g × 10.1°C = 27.3 J
Answer:
Equation 2, because K being more reactive, exchanges position with Pb in PbNO3.
Explanation:
